Civil Engineering Reference
In-Depth Information
1. Cracking moment:
E
E
200,000
4,700
s
n
== =
8.51
25
c
=
π
×
2
2
A
22.225
× =
3
1164 mm (Table A-1)
s
4
bh
h
(
)
+−
+−
=
××+× ×
nAd
1
s
300
700
350
7.5
1164
641
2
y
=
=
362 mm
(
)
bh
nA
1
300
×+×
700
7.5
1164
s
2
3
bh
h
(
)
(
)
2
I
=
+ −+−
bh
y
n
1
Ad y
−
gt
s
12
2
300
×
700
12
3
(
)
2
(
)
2
=
+××
300
700
350
− +× ×−
362
7.5
1164
641
362
9
4
4
=
9.285
×
10
mm
=
0.009285 m
f
=
0.62
f
=
0.62 25
=
3.1MPa
r
c
(
)
Mhy
I
−
3.10.009285
700
×
−
cr
f
=
M
=
=
0.0852 MN-m
=
85.2kN-m
r
cr
(
)
−
3
362
×
10
gt
2. Stresses at
P
=
30 kN
M
=×=
15
460kN-m
<
85.2kN-m
uncracked section
max
−
3
==
××
=
My
I
60
362 10
0.009285
f
2339.26 kPa .34MPa
=
≈
9.4%
f
cc
c
gt
(
)
(
)
Mh y
I
−
−
3
60
×
700
−
362
×
10
f
=
=
=
2184.17 kPa .18MPa
=
≈
70%
f
ct
r
0.009285
gt
(
)
(
)
n
Md y
I
−
3
−
=×
×−×
60
641
362
10
f
=
8.5
=
15,324.72 kPa
s
0.009285
gt
=
15.32 MPa3.7%
≈
f
y
3. Stresses at
P
=
60 kN
M
=×=
30
4
120 kN-m
>
85.2kN-m
max
Cracked section
Assume elastic behavior
bkd
kd
(
)
=
nA
d d
−
s
2
1
2
kn
A
bd
(
)
2
()
s
2
=
1
− = +ρ−ρ
kk nn n
2
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