Civil Engineering Reference
In-Depth Information
Vd
M
u
V
=λ+
1.9
f
2500
ρ
bd
(2.30)
c
c
w
w
m
=−
4
hd
(2.31)
MMN
m
u
u
8
N
u
V
≤λ +
3.5
f bd
1
(2.32)
c
c
w
500
A
g
and in the case of shear, flexure, and axial tension,
N
u
V
=+ λ
21
fbd
0
(2.33)
c
cw
500
A
g
where N u is negative, N u / A g is in psi, and
f c
100 psi except as in Section 11.1.2.1
of ACI 318-11.
For shear strength of stirrups perpendicular to the axis of member,
Af d
S
v t
V
=
(2.34)
s
For shear strength of stirrups inclined with respect to the axis of member,
(
)
Af
sin os
α+ α
d
v t
(2.35)
V
=
s
S
where S is the stirrup spacing = minimum
(,24")
2
(
)
If
V
>
4
f bd
,
S
=
minimum
d
, 12"
s
c
w
4
V
If
V
,
se
A
c
u
v
,min
2
with exceptions in Section 11.4.6.1 of ACI 318-11
bS
f
, 50
bS
f
w
yt
w
yt
(2.36)
A
=
max
0.75
f
v
,min
c
Search WWH ::




Custom Search