Civil Engineering Reference
In-Depth Information
0.35
M
n
f
y
f´
c
f
y
f
c
0.30
= ρ
ρ
1-0.59
bd
2
f
´
c
0.25
0.20
M
n
bd
2
f
c
0.15
0.10
0.05
0
0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45
f
y
ρ
f´
c
FIGURE 2.4
Tests from 364 beams governed by tension. (Courtesy of Portland Cement
Association, 2013
.)
Substituting =
a
1
from the force equilibrium, Equation (2.3),
M
bd
f
f
Af
bdf
n
y
sy
=ρ
1
−
2
f
2*0.85
c
c
c
M
bd
f
f
f
f
n
y
y
=ρ −ρ
1
0.59
(See Figure 2.4)
(2.9)
2
f
c
c
c
)
(2.10)
R
=ω −ω
(1
0.59
where
f
f
M
bd
y
n
ω=ρ
,
R
=
2
f
c
c
2
R
=ω−ω
0.59
(AnalysisEquation)
(2.11)
2
0.59
ω−ω+ =
R
0
ω=
−−
R
112.36
1.18
(Design Equation)
(2.12)
2.2.4 C
onStitutive
r
elationShipS
Concrete is strong in compression and weak in tension because of structural crack-
ing at a relatively low level of stress. Therefore, concrete needs to be reinforced with
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