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φ
φ = 0.75 + (ε t - 0.002) (50)
0.90
Spiral
0.75
φ = 0.65 + (ε t - 0.002) (250/3)
0.65
Other
Compression
controlled
Tension
controlled
Transition
ε t = 0.002
ε t = 0.005
c
c = 0.375
= 0.600
d t
d t
Interpolation on c / d t :Spiral φ = 0.75 + 0.15[(1/ c / d t ) - (5/3)]
Other φ = 0.65 + 0.25[(1/ c / d t ) - (5/3)]
FIGURE 2.1 Change of ϕ factor with net tensile strain in extreme steel bars (ε t ) or neutral-
axis depth ratio ( c / d t ) for Grade 60 reinforcement. (Courtesy of ACI 318-11.)
as seen in Figure 2.2b. The strain profile at steel yielding and ultimate capacity are
illustrated in Figure 2.2. At a level of tensile steel strain (ε t = 0.004) when compres-
sive extreme concrete fiber strain reaches concrete crushing (ε cu = 0.003), the value
of c / dt = 0.429 results from similar triangles (Figure 2.2b), which corresponds to a
factor ϕ = 0.817 for members other than those with spiral steel (Figure 2.1).
2.2.2 F orCe e quilibrium
To determine the location of the neutral axis in beams, force equilibrium needs to
be satisfied as follows:
Analysis problem:
C = T
(2.1)
ε cf
0.003
c y
c
α f ´ c b c y
α f ´ c b c
φ y
φ n
d t
d t
h
A s f y
ε y
A s f y
h
ε s ≥0.004
(a)
(b)
FIGURE 2.2
Strain and force profile at (a) first steel yielding and (b) ultimate capacity.
 
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