Civil Engineering Reference
In-Depth Information
It is important to mention here that
f
cc
and ε′
ccu
for points B and C are deter-
mined from Equations (7.6), (7.8), and (7.9) by computing
f
l
in Equation (7.7) using
ε
fe
= 0.004 instead of κ
ε
ε
fu
used for pure axial compression.
7.3.1.2 Contribution of Steel
The following computation steps are taken in general:
1. The angle between each two consecutive bars is
360
No.ofbars
θ=
bar
(7.41)
2. The radius of bars is
D
d
bar
R
=− −
clear cover
d
−
(7.42)
bar
spiral
2
2
3. The depth of each bar measured from the top extreme fiber is
D
d
=+ −×θ
R
cos(
j
1)
(7.43)
_
barj
bar
bar
2
Note that the first bar is placed on the vertical axis on the tension side of the sec-
tion (bottom side).
4. The strain and stress in the steel bar is
ε=
−
cd
c
_
barj
ε
sj
ccu
(7.4 4)
f
=ε≤
E
f
sj
s j
y
and
f
cj
from Equation (7.3) by substituting ε
sj
for ε
c
.
5. The axial force (
P
sn
) and the bending moment (
M
sn
) contribution of steel are
∑
P
=
(
f
−
f
)
×
A
sn
sj
cj
s bar
,
j
D
∑
M
=
(
f
−
f
)
×
A
×
−
d
(7.45)
sn
sj
cj
s bar
,
_
barj
2
j
The axial force and bending moment capacity of the section is the simple sum of
the contribution of concrete and steel:
PP P
=+
n
c
n
s
n
(7.4 6)
MM M
=+
n
c
n
s
n
Search WWH ::
Custom Search