Civil Engineering Reference
In-Depth Information
Solution:
L
L
1000
1100
af
a
Plate debonding is more likely to occur than cover
delamination (Rasheed, Larson, and Nayyeri Amiri 2013).
=
=
0.91
>
0.9
30
ε=
0.41
=
0.00497
<
0.9
C
ε=
0.00641
fd
E u
3
×
400,000
×
0.17
Determine the failure mode (whether ductile crushing or debonding):
β=
0.85
1
=β
ε×
ε+ε
d
0.003
×
400
max
cu
f
a
=
0.85
×
=
127.95 mm
1
b
0.003
+
0.00497
cu
fd
assuming
b
ε=
, since it is a research specimen (strengthening happened under
self-weight).
0
max
f
f
f
f
a
d
c
b
y
ρ=
max
0.85
−ρ
f
s
fd
fd
f
=
400,000
×
0.00497
=
1, 988 MPa
fd
30
1988
127.95
350
398
300
340
1988
max
ρ= ×
0.85
×
−
×
=
0.00404
f
×
350
ρ=
××
×
3
300
0.17
=
0.001457
< ρ
max
debonding controls
f
f
300
350
α+=+
fbcAf
Af
Af
c
s s
s y
f fd
2
2
α=
ε
ε
1
3
ε
ε
c
1
3
c
cf
c
cf
c
−
=
2.50
400
−
2.50
400
c
c
−
−
ε=
ε
c
dc
c
fd
where
=
0.00497
400
cf
−
−
c
f
f
c
−
4
ε=
1.71
4700
=
3.64
×
10
f
=
0.00199
c
c
f
c
(
)
ε=
ε −
−
cd
dc
c
−
50
fd
=
0.00497
s
400
−
c
f
Substituting these expressions into the force equilibrium equation,
c
c
2
c
50
−
2.50
×
−
−×
−
2.1
×× +× ×
30
300
c
265
200000
0.00497
2
400
c
(400
c
)
400
−
c
=×+×
398
340
153
1988
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