Civil Engineering Reference
In-Depth Information
The slab is a two-span, continuous, solid, one-way slab with the following
parameters:
w
LL
=
4.8 kN/m
2
w
LL
upgrade
=
7. 0 k N / m
2
f
y
=
400 MPa
f
c
=
25 MPa
Solution:
Let
h
L
===
Use
h
=
0.2 m
=
200 mm
DL
self wt: 0.2
×
23.6
=
4.72 kN/m/m
DL
tiling: 0.05
×
17
=
0.85 kN/m/m
DL
total:
W
DL
=
5.57 kN/m
2
LL
total:
W
LL
=
4.8 kN/m
2
5.5
28
0.196 m
min
28
wL
n
9
wL
n
14
wL
n
24
-
-
As per ACI 318-83:
ww w
u
=
1.4
+
1.7
DL
LL
15.96 kN/m
2
=×+×=
1.45.571.7
4.8
d
=
200 − 25
=
175 mm
w
un
2
M_@interior_support
=
=
53.64 kN-m/m
9
6
M
fbd
53.64
× −
×× ×
10
Nmmm
/
u
R
=
φ
=
=
0.0778
2
2
0.925
1000
175
c
ω=
−−
=
112.36
1.18
R
0.0818
f
f
25
400
c
ρ=ω= ×
0.0818
=
0.00511
s
y
2
Abd
s
=ρ =
0.00511
× ×=
1000
175
895 mm /m
1
s
Try No. 13 bars (Area
=
133 mm
2
).
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