Digital Signal Processing Reference
In-Depth Information
The noise is now to be calculated as mean-square quantization error, e 2 where
e is the difference between the actual and approximated value of voltage/current.
The peak to peak amplitude of the sampled signal x s (
is divided into M equal
levels each of width S. At the centre of each level of width the quantization levels
are located as x 1 , x 2 ,
t
)
happens
to be the closest to the level x k , the quantizer output will be x k and obviously, the
quantization error is e
...
x M as shown the Fig. 2.14 . Since, in the figure x s (
t
)
=
x s ( t )
x k .
Fig. 2.14 Interpretation of
quantization error
x S
x k
x 3
x 2
x 1
Let, p ( x ) dx be the probability that x s (
t
)
lies in the voltage/current range x
+
dx
/
2
to x
dx
/
2. Then the mean square quantization error [ 3 ]is
x 1 + S / 2
x 2 + S / 2
2 dx
2 dx
e 2
=
p ( x )
(
x
x 1 )
+
p ( x )
(
x
x 2 )
+ ...
(2.11)
x 1
S
/
2
x 2
S
/
2
Now, the PDF (probability density function) p ( x ) of the message signal will not
certainly be constant throughout each division. Assuming large M , i.e., with suffi-
ciently small S , p ( x ) can be taken as constant throughout each division. Then, the 1st
term of the right hand side of the Eq. ( 2.11 ), p ( x )
p ( 1 ) =
=
constant. The 2nd term is
p ( 2 ) , and so on. Hence, the constant terms may be taken out of the integration
sign. If we now substitute y
=
p ( x )
x
x k , the expression in Eq. ( 2.11 ) becomes
S
/
2
p ( 1 ) +
p ( 2 ) + ...
y 2 dy
e 2
=
S
/
2
p ( 1 ) +
S 3
12
(2.12)
p ( 2 ) + ...
=
p ( 1 ) S
S 2
12
p ( 2 ) S
=
+
+ ...
Now, according to definition, p ( 1 ) S be the probability that the signal lies within the
1st quantization range, p ( 2 ) S be the probability that the signal lies within the 2nd
quantization range, and so on. Hence, the sum of the terms in the bracket in the
 
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