Digital Signal Processing Reference
In-Depth Information
Unequalized output
τ
τ
τ
τ
τ
c N
c N +1
c 0
c N −1
c N
Tap gain
adjustment
algorithm
Equalized output
Fig. 5.10 Linear transversal filter
N
g E ( t )
=
c n δ (
t
n
τ )
(5.22)
n
=−
N
and the corresponding frequency response is
N
c n e j 2 π fn τ
G E ( f )
=
(5.23)
n
=−
N
Since, P ( f )
G T ( f ) H ( f ) G R ( f ), and p(t) is the inverse Fourier transform of P(f),
the equalized output signal pulse
=
N
q ( t )
=
c n p
(
t
n
τ )
(5.24)
n
=−
N
Applying the zero forcing condition at t
=
mT B ,
N
q ( mT B )
=
c n p
(
mT B
n
τ )
; m
=
0,
±
1,
±
2, ...
±
N
(5.25)
n
=−
N
Since, there are 2N+1 equalizing coefficient, we can control only 2N+1 sampled
values of q(t). Specially,
1, m
N
=
0
q ( mT B )
=
c n p
(
mT B
n
τ ) =
(5.26)
0, m
1,
±
2, ...
±
N
n =− N
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