Digital Signal Processing Reference
In-Depth Information
Unequalized output
τ
τ
τ
τ
τ
c
−
N
c
−
N
+1
c
0
c
N
−1
c
N
Tap gain
adjustment
algorithm
Equalized output
Fig. 5.10
Linear transversal filter
N
g
E
(
t
)
=
c
n
δ (
t
−
n
τ )
(5.22)
n
=−
N
and the corresponding frequency response is
N
c
n
e
j
2
π
fn
τ
G
E
(
f
)
=
(5.23)
n
=−
N
Since,
P
(
f
)
G
T
(
f
)
H
(
f
)
G
R
(
f
), and p(t) is the inverse Fourier transform of P(f),
the equalized output signal pulse
=
N
q
(
t
)
=
c
n
p
(
t
−
n
τ )
(5.24)
n
=−
N
Applying the zero forcing condition at t
=
mT
B
,
N
q
(
mT
B
)
=
c
n
p
(
mT
B
−
n
τ )
;
m
=
0,
±
1,
±
2, ...
±
N
(5.25)
n
=−
N
Since, there are 2N+1 equalizing coefficient, we can control only 2N+1 sampled
values of q(t). Specially,
1,
m
N
=
0
q
(
mT
B
)
=
c
n
p
(
mT
B
−
n
τ )
=
(5.26)
0,
m
=±
1,
±
2, ...
±
N
n
=−
N
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