Geography Reference
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where K is the eddy viscosity in the ocean (assumed constant). As a lower
boundary condition assume that u, v
10 3 m 2 s 1 ,
what is the depth of the surface Ekman layer at 43˚N latitude?
0asz
→−∞
.IfK
=
5.7. Show that the vertically integrated mass transport in the wind-driven oceanic
surface Ekman layer is directed 90˚ to the right of the surface wind stress in
the Northern Hemisphere. Explain this result physically.
5.8. A homogeneous barotropic ocean of depth H
3 km has a zonally sym-
metric geostrophic jet whose profile is given by the expression
=
U exp
(y/L) 2
u g =
1m s 1
=
=
where U
200 km are constants. Compute the vertical
velocity produced by convergence in the Ekman layer at the ocean bottom
and show that the meridional profile of the secondary cross-stream motion
forced in the interior is the same as the meridional profile of u g . What are
the maximum values of
and L
10 - 3 m 2
s - 1
v in the interior and
¯
w if K
¯
=
and
10 4
s 1 (Assume that w and the eddy stress vanish at the surface.)
f
=
5.9. Using the approximate zonally averaged momentum equation
u
∂t =
¯
f
v
¯
compute the spin-down time for the zonal jet in Problem 5.8.
5.10. Derive a formula for the vertical velocity at the top of the plane ta ry boundary
layer using the mixed layer expression (5.22). Assume that
5ms 1
|
V
|=
is independent of x and y and that
0.05,
what value must K m have if this result is to agree with the vertical velocity
derived from the Ekman layer solution at 43˚ latitude with De
u g
¯
u g (y).Ifh
=
1kmandκ s =
=
1 km?
5.11. Show that K m =
kzu in the surface layer.
MATLAB EXERCISES
M5.1. The MATLAB script mixed layer wind1.m uses a simple iterative tech-
nique to solve for u and v in (5.22) with u g in the range 1-20 m s 1
for
0.05 m 1 s. If you run the script, you will
observe that this iterative technique fails for u g greater than 19 m s 1 .An
alternative method, which works for a wide range of specified geostrophic
winds, utilizes the natural coordinate system introduced in Section 3.2.1.
the case v g
=
0 and κ s
=
 
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