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Note that
| E | =
0 for the linear polarization, and
| E | =
1 for the circular
polarization. What is the sense of the sign of
E ? Let us define the angle velocity of
the field rotation:
dt arctan E y ( t )
d
| E x || E y |
E
=
E x ( t ) =
sin
) .
2 cos 2 (
2 cos 2 (
E
y
| E x |
t
x )
+| E y |
t
E
This makes clear that the electric vector rotates clockwise if sin
>
0, that is,
E < 0, that is, for
for
E < 0.
With (2.14), we can present simple formulae for normalized semi-axes of polar-
ization ellipse:
E >
0, and counterclockwise if sin
a E
a E +
1
1
b E =
=
1
E =
cos
,
E
tan 2
+
b E
a E
1
+
(2
.
15)
b E
a E +
1
tan
E
b E =
=
1
E =
sin
E .
tan 2
+
a E
b E
1
+
It is obvious that the polarization state of the electric field is completely deter-
mined by its polarization ratio. The complex quantity P E =
E e i
E
tan
characterizes
E x | , E y and
E
E
the entire class of electric fields with different
|
x ,
y , but with
E y / |
E
E
y
x and hence with the same elliptic
the same tan
=
E x |
,
=
parameters
E which define the orientation and shape of the polarization ellipse.
According to (2.13), (2.14)
,
E
E cos
E
tan 2
E =
tan 2
/
2
E /
2
(2
.
16)
E sin
E
E =
tan
E
sin 2
E =
sin 2
1
≤ ≤
1
/
4
E /
4
.
Converting these relationships, we get
E
E
cos 2
=
cos 2
E cos 2
0
/
2
E
(2
.
17)
E
E
tan
=
tan 2
E csc 2
<
.
E
Similar formulae are available for the polarization ellipse of the magnetic field
(Fig. 2.1b).
The angle
H between the major axis of the magnetic ellipse and the x -axis can
be determined from the equation
2Re P H
H cos
H
tan 2
=
2 =
tan 2
(2
.
18)
H
1
− |
P H
|
 
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