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G ( M
,
M v )
| =−
( r MM v )
G ( M
,
M v )
| S =
0
.
(1
.
108)
Thus,
grad
V
G ( M
,
M v ) di
v
j ( M v ) dV
M
V
j p ( M )
=
(1
.
109)
0
M
V
.
Next we will pass on to the solenoidal part j s .Define j s as
curl I ( M )
M
V
j s ( M )
=
(1
.
110)
0
M
V
,
where I can be considered as the magnetization of a magnetic body that is equivalent
to the solenoidal current of the density j s distributed within the domain V. Note that
(1.110) does not provide the unique determination of j s . Evidently j s can be also
taken as
curl I ( M )
j s ( M )
=
M
V
,
(1
.
111)
where
I ( M )
=
I ( M )
+
grad
( M )
and
is arbitrary scalar function. But we eliminate such an arbitrariness by impos-
ing the requirement that di
v
I
=
0
.
So, we write
curl I ( M )
=
j s ( M )
di
v
I ( M )
=
0
M
V
,
(1
.
112)
whence, with due regard for (1.104),
=−
=−
.
.
I ( M )
curl j s ( M )
curl j ( M )
(1
113)
Now, using the Green function introduced by (1.108), we find
G ( M
,
M v ) curl j ( M v ) dV
M
V
I ( M )
=
(1
.
114)
V
.
0
M
V
Here the curl may be taken out of the integral. Since di
v
I
=
0, we express I as
I
=
curl P , where P is a vector field. Then (1.113) assumes the form
P
=−
j ,
whence
G ( M
,
M v ) j ( M v ) dV
M
V
=
(1
.
115)
P ( M )
V
0
M
V
.
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