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Fig. 1.3 Rotation of a
reference frame
Thus,
)] 1 [ R (
E (
)
=
[ R (
)] E =
[ R (
)][ Z ] H =
[ R (
)][ Z ][ R (
)] H
=
[ Z (
)] H (
)
,
where
) ] 1
[ Z (
)]
=
[ R (
)][ Z ][ R (
.
(1
.
25)
In full form, we have
= Z xx cos 2
+ Z yy sin 2
Z xx (
)
+
( Z xy + Z yx )sin
cos
Z xy cos 2
Z yx sin 2
=
( Z xx
Z xy (
)
Z yy )sin
cos
(1
.
26)
= Z yx cos 2
Z xy sin 2
Z yx (
)
( Z xx Z yy )sin
cos
Z yy cos 2
Z xx sin 2
Z yy (
)
=
+
( Z xy +
Z yx )sin
cos
or
Z xx (
)
= Z 2 + Z 3 sin 2
+ Z 4 cos 2
Z xy (
)
= Z 1 + Z 3 cos 2
Z 4 sin 2
(1
.
27)
Z yx (
)
=− Z 1 + Z 3 cos 2
Z 4 sin 2
Z yy (
)
= Z 2 Z 3 sin 2
Z 4 cos 2
,
where
Z xy Z yx
2
Z xx + Z yy
2
Z 1 =
Z 2 =
Z xy + Z yx
2
Z xx Z yy
2
Z 3 =
Z 4 =
.
One can readily see that
=
+
=
+ /
Z xx (
)
Z xx (
)
Z yy (
2)
Z xy (
)
=
Z xy (
+
)
=−
Z yx (
+ /
2)
(1
.
28)
Z yx (
)
= Z yx (
+
)
=− Z xy (
+ /
2)
Z yy (
)
= Z yy (
+
)
= Z xx (
+ /
2)
.
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