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1
2
(
S
1
e
yy
−
S
1
S
1
)
Z
N
h
xx
=
1
+
for
|
y
|
<
b
S
1
=
(7
.
124)
S
1
1
2
(
S
1
e
xx
−
for
|
y
|
>
b
.
S
1
)
Z
N
h
yy
=
1
+
,
At the last stage, we substitute (7.120), (7.121), (7.123) into (1.74) and determine
0
Z
xy
[
Z
]
=
,
(7
.
125)
Z
yx
0
where
e
xx
Z
xy
=
1
1
S
1
)
Z
N
+
2
(
S
1
e
xx
−
(7
.
126)
e
yy
Z
yx
=−
S
1
)
.
1
1
Z
N
+
2
(
S
1
e
yy
−
Finally,
Z
xy
Z
yx
2
2
o
,
xy
=
yx
=
(7
.
127)
o
where
xy
S
1
S
1
=
yx
S
1
S
1
for
|
y
|
>
b
=
yx
b
a
xy
a
b
for
|
y
|
<
b
.
Let us consider the apparent resistivities
xy
and
yx
outside the inclusion (
|
y
|
>
b
).
According to (7.120), (7.125) and (7.127),
xy
˙
n
in the
S
1
−
interval
|
y
|
>
b
=
xy
xy
˙
n
in the
h
−
interval
(7
.
128)
yx
˙
n
in the
S
1
−
interval
yx
|
y
|
>
b
=
yx
˙
n
in the
h
−
interval
,
n
n
in the
S
1
−
where the locally normal apparent resistivities ˙
,
˙
and
h
−
intervals
are
1
o
(
S
1
)
2
,
n
n
=
o
h
2
˙
=
˙
and the 3D-distortion factors are
