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where the bars denote the complex conjugation. With account for (1.27),
Im Z 2 +
=
Z 1 +
Z 3
Z 4
Z 3
Z 4
sin 2
+
cos 2
cos 2
sin 2
0
Im Z 1 +
Z 2
=
Z 3 cos 2
Z 4 sin 2
Z 3 sin 2
Z 4 cos 2
0
.
Expanding and simplifying these equations, we obtain
A sin 2
B cos 2
+
C
=
0
,
A sin 2
B cos 2
C
=
0
,
(3
.
6)
where
Im Z xx Z yy +
Z xy Z yx
A
=
Im Z yx Z xx +
Z xy Z yy
B
=
Im Z xy Z yy +
Z xx Z yx =
B Z xy
Z yx
2
C
=
ske
w
.
=
w
=
Taking into account that C
0 when ske
0, we write
B
A sin 2
B cos 2
=
0
,
(3
.
7)
whence
2 arctan Im Z yx Z xx +
Z xy Z yy
1
2
B
A =
1
R
Im Z xx Z yy +
Z xy Z yx =
=
arctan
(3
.
8)
+ 2 ,
R
where
R is a strike angle of the regional two-dimensional structure. Applying the
Bahr method, we specify the principal directions,
R and
+ /
2, of the regional
R
impedance [ Z R ].
Let ske
0 because of measurement noises and asymmetry of regional struc-
ture. In that event
w
=
B
A sin 2
B cos 2
+
C
=
0
,
A sin 2
B cos 2
C
=
0
.
Departure of these equations from 0 can be characterized by the quadratic deviation
C ) 2
C ) 2
(
)
=
( A sin 2
B cos 2
+
+
( A sin 2
B cos 2
.
(3
.
9)
At a minimum of
) we have the least disagreement between phases in columns
of the tensor [ Z S ]. Solving the equation d
(
/
=
0 with d 2
/
2
>
(
)
d
(
)
d
0, we
min
R
find an angle
which minimizes
(
). By virtue of (3.9)
 
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