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3) Carry out consistency test to judgment matrix
In order to testing the consistency of judgment matrix
A
, it is required to calculate the
consistency index
, and it is considered that the judgment matrix must
be satisfied consistency when the random consistency ratio
C
.
R
.
=
C
.
I
R
.
I
.Otherwise
C
.
R
.
<
0
.
10
need to adjust the judgment matrix in order to get satisfied consistency.
Carry out
RC
of judgment matrix
A
, so there is good consistency. At
the same time, we examine all judgment matrix with the same way and obtain good
result.
4) determine index weight
Carry out weight set of each factors classes and each factor by the above method:
.
=
0
0011
<
0
10
K
=
(
K
,
K
,
K
,
K
,
K
,
K
)
=
(
085
,
281
,
354
,
055
,
093
,
132
)
1
2
3
4
5
6
K
=
(
K
,
K
,
K
)
=
(
0
0
0
1
11
12
13
K
=
(
K
,
K
,
K
)
=
(
240
,
623
,
137
)
K
=
(
K
,
K
,
K
,
K
,
K
)
=
(
396
,
24
,
24
,
074
,
05
)
2
21
22
23
3
31
32
33
34
35
K
=
(
K
,
K
,
K
)
=
(
164
,
297
,
539
)
K
=
(
K
,
K
,
K
)
=
(
25
,
25
)
4
41
42
43
5
51
52
53
K
=
(
K
,
K
,
K
,
K
)
=
(
239
,
239
,
089
,
433
)
6
61
62
63
64
3.3 Setting the Comprehensive Evaluation
Evaluation results indicated that with the fuzzy evaluation matrix
L
, the
R
i
(
i
=
1
2
,
6
)
evaluation results of
can be show with
.Then evaluating first-
U
i
(
i
=
1
L
6
B
i
(
i
=
1
2
,
L
6
)
Level indicators, In which the fuzzy evaluation matrix is
T
.
R
=
(
B
,
B
,
B
,
B
,
B
,
B
)
1
2
3
4
5
6
Finally, it obtained comprehensive assessment results
B
=
C
⋅
R
=
(
b
,
b
,
L
b
)
. The
1
2
evaluation matrix of first-level indicators as follows:
0
0
4
0
0
0
3
0
6
0
.
1
0
⎡
⎤
⎡
⎤
⎢
⎥
⎢
⎥
R
=
0
0
2
0
0
R
=
0
.
2
0
.
0
.
1
0
⎢
⎥
⎢
⎥
2
⎢
0
0
5
0
0
⎥
⎢
0
.
2
0
.
0
0
⎥
⎣
⎦
⎣
⎦
0
.
3
0
.
7
0
0
⎡
⎤
0
0
0
0
⎡
⎤
⎢
⎥
⎢
⎥
0
.
1
0
.
6
0
.
0
R
=
0
0
0
2
0
⎢
⎥
⎢
⎥
R
=
⎢
0
.
0
.
0
0
⎥
⎢
0
0
0
0
⎥
⎢
⎥
⎣
⎦
0
.
0
.
5
0
0
⎢
⎥
⎢
⎥
0
.
6
0
.
4
0
0
⎣
⎦
0
0
0
0
⎡
⎤
⎡
0
0
5
0
0
⎤
⎢
⎥
⎢
⎥
R
=
0
0
0
0
0
0
0
3
0
⎢
⎥
⎢
⎥
R
=
6
⎢
⎥
⎢
0
0
.
7
.
0
0
1
⎥
0
0
0
0
⎣
⎦
⎢
⎥
0
0
0
3
0
⎣
⎦
K
=
(
0
400
,
0
.
200
,
.
400
)
K
=
(
0
240
,
0
.
623
,
0
.
137
)
1
2
K
=
(
396
,
240
,
240
,
074
,
050
)
K
=
(
0
.
164
,
0
.
297
,
.
539
)
K
=
(
0
.
250
,
0
.
500
,
0
250
)
3
4
5
K
=
(
0
239
,
.
239
,
0
089
,
0
433
)
6
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