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α
2
2
3
a
=
0,
a
=
C
,
ω
=
(3
β
12
α
a
+
a B
) / 4
α
.
(10)
1
2
0
4
and
0 aABC are arbitrary constants.
The traveling wave solution of the KP-type equation are given by
,
,
,
α
C
2
Ua
()
ξ
=+
F
(),
ξ
0
4
where
ξ
=++
α
x
β
y
ω
t
,
ABC
,,,,
α β
are arbitrary constants, and
a
2 ,
ω
are given
in (10).
From the proposition, if we choose
2
2
2
2 (0)
B
=
ϑ
CA
=−
=−
ϑϑ
(0)
(0)
and
2
4
2
4 (0),
ϑ
we can get the solution to the KP-type equation in terms of theta functions:
2 ()
ϑ
ξ
α
C
1
uxyt
(, ,)
=
a
+
,
(11)
0
2
4
ϑ
()
ξ
3
a
2 ,
ω
where,
are given in (10).
To grasp the characteristc of solutions of (1), we dipict the figure of the solution
(, ,)
ABC
,,,,
α β
are arbitrary constants, and
uxyt by using the mathematica, their properties and profiles are displayed in fig-
ures (1)-(4) under chosen parameters:
3,
ac d
===
1
,
α
===
1,
βγ
8,
0
,
C
=−
1
and
t
=
2
for 2D figure (3),
x
=
2
for 2D figure (4).
From figures (1)-(4), it is easy to see that the solution
uxyt is periodic wave
( ,
, )
solution.
 
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