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Taking limits on the both sides of the above inequality as
k
∈
K
i
,
k
→
∞
, according
to
lim
f
=
f
*
=
lim
f
,
we obtain
k
l
(
k
)
k
∈
K
,
k
→
∞
k
→
∞
i
l
i
,
α
λ
g
=
0
.
(2.8)
k
k
k
k
∈
K
k
→
∞
i
By (2.3), we have
li
,
α
λ
=
0
.
(2.9)
k
k
k
∈
K
k
→
∞
i
α
λ
′
It follows from (2.9), Armijo rule and NNLS that if
ψ
=
k
and
ψ
=
k
at least
k
k
γ
γ
one of the following three inequalities holds for
k
∈
K
sufficiently large.
i
g
(
x
+
ψ
d
),
d
>
μ
g
,
d
.
k
k
k
k
0
k
k
2
g
(
x
+
ψ
d
),
g
<
μ
g
(
x
+
ψ
d
)
.
k
k
k
k
1
k
k
k
1
′
′
′
f
(
x
+
ψ
P
)
>
max
f
+
σ
[
g
T
k
P
+
ψ
P
T
B
P
].
k
k
k
k
−
j
k
k
k
k
k
k
2
0
≤
j
≤
m
(
k
)
But whichever holds, similar to the proof of Lemma 2.4 in [5], by using (2.3),(2.8)
1
and (2.9), we can obtain the corresponding
μ
≥
1
i
=
0
),
σ
>
,
which is a
i
2
contradiction. Therefore we have
li
,
g
=
0
k
k
∈
K
k
→
∞
i
(2) Similar to the proof of (2) in Lemma 2.4
[5]
, we can obtain the conclusion
easily.
Analogous to the proof of Theorem 2.1 in [5], it is easy to prove the following
theorem.
{}
Theorem 2.1.
Suppose that
k
x
is an infinite iteration sequence generated by
Algorithm 2.1. If there exists an open convex set
D
containing
{}
k
x
such that
g
(
x
)
{}
k
is uniformly continuous on
D
, then either
lim
g
=
−∞
or
f
converges to a finite
k
k
→
∞
value and
lim
g
=
0
k
k
→
∞
By Theorem 2.1, the following corollary is obvious.
Corollary 2.1.
Suppose that the assumption conditions of Theorem 2.1 hold. If the
infinite iteration sequence
{}
k
x
generated by Algorithm 2.1 has cluster point
*
x
, then
x
*
∈
Ω
*
.
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