Cryptography Reference
In-Depth Information
may not be possible to divide two arbitrarily chosen elements. For example, in the
ring
Z
, + ,
·
it is possible to divide 6 by 2, but it is not possible to divide 2 by 3.
such
that b = ac . Alternatively speaking, a is a divisor of b and b is said to be a multiple
of a . In the examples given earlier 2
For a, b
Z
, we say that a divides b , denoted as a
|
b , if there exists a c
Z
3, but 3 does not divide 2.
Also, 1 divides every integer and the largest divisor of any integer a
|
6, because 6=2
·
Z \{
0
}
is
|
a
|
.
Furthermore, every integer a
divides 0; thus 0 has no largest divisor. Theorem
3.2 enumerates some rules that can be used to compute with divisors.
Z
Theorem 3.2 Fo r a l l a, b, c, d, e
Z
, the following rules apply:
1. If a
|
b and b
|
c ,then a
|
c .
2. If a
|
b ,then ac
|
bc for all c .
3. If c
|
a and c
|
b ,then c
|
da + eb for all d and e .
4. If a
|
b and b
=0 ,then
|
a
|≤|
b
|
.
5. If a
|
b and b
|
a ,then
|
a
|
=
|
b
|
.
Proofs.
1. If a
with b = af and c = bg . Consequently,
we can write c = bg =( af ) g = a ( fg ) to express c as a multiple of a .The
claim (i.e., a
|
b and b
|
c , then there exist f, g
Z
|
c ) follows directly from this equation.
2. If a
with b = af . Consequently, we can write
bc =( af ) c = f ( ac ) to express bc as a multiple of ac . The claim (i.e., ac
|
b , then there exists f
Z
|
bc )
follows directly from this equation.
3. If c
with a = fc and b = gc . Consequently,
we can write da + eb = df c + egc =( df + eg ) c to express da + eb as
a multiple of c . The claim (i.e., c
|
a and c
|
b , then there exist f, g
Z
|
da + eb ) follows directly from this equation.
4. If a
|
b and b
=0, then there exists 0
= f
Z
with b = af . Consequently,
|
b
|
=
|
af
|≥|
a
|
and the claim (i.e.,
|
a
|≤|
b
|
) follows immediately.
5. Let us assume that a
|
b and b
|
a .If a =0then b =0, and vice versa. If a, b
=0,
then it follows from 4. that
|
a
|≤|
b
|
and
|
b
|≤|
a
|
, and hence
|
b
|
=
|
a
|
.
Theorem 3.3 elaborates on the division operation and is commonly known as
Euclid's division theorem for integers. We don't prove the theorem in this topic.
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