Biomedical Engineering Reference
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• W ð 0 Þ¼ 0;
• The increments, W ð t k þ 1 Þ W ð t k Þ and W ð t k Þ W ð t k 1 Þ are independent for any
0 t k 1 \t k \t k þ 1 ;
• For 0 s t ; the increment W ð t Þ W ð s Þ has the Gaussian distribution with
mean 0 and variance t s ; i.e. W ð t Þ W ð s Þ N ð 0 ; t s Þ:
Further, W ð t Þ is 'stochastically continuous' (lim t ! s P ðj W ð t Þ W ð s Þj [ Þ¼ 0),
where P stands for the probability. The formal analytic solution,
X ð t Þ¼ X 0 þ rW ð t Þ;
Y ð t Þ¼ Y 0 þ rW ð t Þ;
Z ð t Þ¼ Z 0 þ rW ð t Þ;
ð 2 Þ
for t [ 0 ;
can be given, however the differential form is more useful in this study from a
practical point of view. The equations are classically numerically solved using the
Euler-Maruyama Method, given by
X i þ 1 ¼ X i þ rDW i þ 1 ;
X 0 ¼ð X 0 ; Y 0 ; Z 0 Þ:
ð 3 Þ
Here each component of DW is a normally distributed stochastic parameter with
zero mean and variance Dt ; denoted by N ð 0 ; Dt Þ; and it can be proved that [ 24 ]
each component m satisfies DW i þ 1 ¼ W i þ 1 W i N ð 0 ; 1 Þ
p
; in other words, a
Gaussian distribution with zero mean and a variance of Dt : We show a run of the
solution of the stochastic differential equations with one bacterium initially located
at ð 0 ; 0 ; 0 Þ with mobility r ¼ 2 : 6833 10 5 m/
Dt
p : This value was chosen from
[ 25 ] and corresponds to the classical bacillum in Fig. 1 . Figure 1 shows the tra-
jectory of the bacterium over time in three dimensions. Since Fig. 1 only gives one
specific run, the trajectory itself is a stochastic parameter and hence for many
purposes the probability density function is of more importance. To this extent,
since dW ð t Þ N ð 0 ; 1 Þ
p
and W ð t Þ N ð 0 ; 1 Þ t
p
; the probability density for the
position of the bacterium at time t for each coordinate direction satisfies
dt
exp ð ð m m 0 Þ 2
2r 2 t
1
2pr 2 t
p
f m ð t ; m Þ¼
Þ;
m X ; Y ; Z Þ:
ð 4 Þ
Since the Brownian motion in each coordinate direction is an independent
stochastic event, the multi-variate probability density is given by
ð 2pr 2 t Þ 2 exp ð ð x X 0 Þ 2
1
f ð x ; y ; z Þ¼
Þ;
ð 5 Þ
2r 2 t
3
which solves the initial value problem in R
ot r 2
of
2 Df ¼ 0 ;
f ð 0 ; ð x ; y ; z ÞÞ ¼ d ð x X 0 Þ:
ð 6 Þ
Here d ð x Þ represents the Dirac Delta Distribution in three dimensions, with
characteristics
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