Biomedical Engineering Reference
In-Depth Information
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Figure 4.2:
Circuit analog of a discrete cable.
i
r
i
r
i
c
m
r
m
r
e
r
e
e
1
2
3
Figure 4.3:
Example node in a discrete cable.
substitution for
i
m
yields
r
e
)
c
m
dV
m
dt
.
V
m
−
2
V
m
+
V
m
V
m
r
m
=
(r
i
−
+
(4.10)
dx
2
If we let
dx
→
0, Eq. (4.10) becomes the continuous cable equation: