Digital Signal Processing Reference
In-Depth Information
The expected value of m ( f ) is obtained by averaging the right-hand side of
Equation (18.11) over the sampling instants
{
t k }
. Then
N
1
N
E [ m ( f )]
=
sin(2 π ft
+ ϕ
) p k ( t )d t
(18.12)
−∞
k
=
1
where p k ( t ) is the probability density function of the time intervals [0
t k ].
Thus the expected value of m ( f ) depends both on the sinusoidal signal param-
eters and on the sampling point process used when sampling this signal. In the
case of periodic sampling with jitter,
,
1
/
T
for t
[( k
1) T
,
kT ]
,
p k ( t )
=
0
for t
[( k
1) T
,
kT ]
.
Substituting this function into Equation (18.12) leads to
N
1
Θ
ω
=
ω
+ ϕ
E [ m (
)]
sin(
t
) d t
( k
1) T
k
=
1
Θ
1
Θ
=
ω
+ ϕ
sin(
t
)d t
0
sin ω 2
sin
ωΘ/
2
=
+ ϕ
,
(18.13)
ωΘ/
2
2 π f and
where
ω =
Θ
is the time interval during which the signal is observed.
In this particular case,
NT . This expected value of E [ m ( f )] of a sine-wave
signal sampled periodically with jitter is shown in Figure 18.1 as a function of the
normalized frequency
Θ =
ν =
f
Θ =
fNT . The two diagrams (a) and (b) illustrate
ϕ = π /
the cases where
0 respectively.
This function is directly tied to the expected values of D c ,
2 and
ϕ =
V c and V s and
therefore also to the expected values of the cross-interference coefficients. While
in the wide frequency range the expected values of these coefficients are mean-
ingless as they are in a wide frequency range close to zero, the function describing
the expected values of them in the low-frequency range is quite useful. The point
is that the expected value of E [ m ( f )] represents a good approximation of the
cross-interference function there.
Basically there are two reasons why the mean value of a sinusoid might differ
from zero. Firstly, it happens if such a signal is observed and the mean value is
calculated for a time interval not equal to an integer number of its periods and,
secondly, the mentioned deviations occur as a result of nonuniform sampling.
Both of these factors often act simultaneously, causing the cross-interference
D s ,
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