Digital Signal Processing Reference
In-Depth Information
k_2
l=(4,1)
4
l=(3,1)
l=(2,1)
3
l_2
l= (4,0)
l= (3,0)
l= (2,0)
l = (1,0)
l=(1,1)
2
1,1
2,1
3,1
4,1
1
l=(0,1)
k_1
l_1
0
1
2
0,0 1.0
2,0
3,0
4,0
2
1
Fig. 4
Ordering of the upsampler's output tokens
For example, consider a source actor S producing (3,3) samples. It thus has a
support matrix Q
=
(
,
)
diag
3
3
. Assume that S is connected to an expander with input
=
sampling matrix V I
I , scanning its input in row scan order. Thus the upsampler
|
(
) |
L
has to output
det
L
samples in a parallelogram
defined by the columns of the
matrix L for every input sample. Suppose
2
2
32
L
=
10. These samples can be ordered as follows.
The first column of L can be interpreted as the upsampler's horizontal direction ,
and the second column as its vertical direction in a generalized rectangle
|
det
(
L
) | =
L
.In
L
,
there are L 1 =
10 samples):
The sampling rate at the output of the upsampler can be chosen to be ( L 2 ,
5 groups of L 2 =
2 samples (that is L 1 ×
L 2 = |
det
(
L
) | =
L 1 ), that is
L 2 rows and L 1 columns in natural order . The relation between the natural ordered
samples and the samples in the generalized rectangle
L
is then
(
,
)
(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)
l 1
l 2
:
0
0
1
0
2
0
3
0
4
0
0
1
1
1
2
1
3
1
4
1
(
,
)
(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)(
,
)
k 1
k 2
:
0
0
0
1
0
2
1
2
1
3
1
1
1
2
1
3
0
3
0
4
This is shown in Fig. 4 .
In this figure,
is shown at the left, and the natural ordering of samples is shown
at the right. The correspondence between samples in
L
L
and the natural ordering of
these samples is displayed at the left as well.
3.1
A Complete Example
Consider the MDSDF graph shown in Fig. 5 [ 13 , 14 ] .
 
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