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The used test statistics in hypothesis testing depends on the hypothesized parameter
and the data collected. In practical comparison studies, most tests involve comparisons
of a mean performance with a certain value or with another software mean. When
the variance (
2
) is known, which rarely is the case in real-world applications,
Z
0
is
used as a test statistic for the null hypothesis H
0
:
σ
µ
=
µ
0
, assuming that the observed
population is normal or the sample size is large enough so that the CLT applies.
Z
0
is
computed as follows:
y
−
µ
0
σ/
√
n
Z
0
=
(6.6)
The null hypothesis
H
0
:
µ
=
µ
0
would be rejected if
|
Z
0
|
>
Z
α
/2
when
H
a
:
µ
=
µ
0
,
Z
0
<
−
µ>µ
0
.
Depending on the test situation, several test statistics, distributions, and com-
parison methods also can be used at several hypothesis tests. Let us look at some
examples.
For the null hypothesis,
H
0
:
Z
α
when
H
a
:
µ<µ
0
, and
Z
0
>
Z
α
when
H
a
:
µ
1
=
µ
2
,
Z
0
is computed as follows:
y
1
−
y
2
Z
0
=
(6.7)
1
2
2
2
n
2
σ
n
1
+
σ
The null hypothesis
H
0
:
µ
1
=
µ
2
would be rejected if
|
Z
0
|
>
Z
α
/2
when
H
a
:
µ
1
=
µ
2
,
Z
0
<
−
Z
α
when
H
a
:
µ
1
<µ
2
, and
Z
0
>
Z
α
when
H
a
:
µ
1
>
µ
2
.
2
) is unknown, which is typically the case in real-world
applications,
t
0
is used as a test statistic for the null hypothesis
H
0
:
When the variance (
σ
µ
=
µ
0
and t
0
is
computed as follows:
y
−
µ
0
t
0
=
/
√
n
(6.8)
s
The null hypothesis
H
0
:
µ
=
µ
0
would be rejected if
|
t
0
|
>
t
α
/2, n
−
1
when
H
a
:
µ
=
µ
0
,t
0
<
−
t
α
,
n
−
1
when
H
a
:
µ<µ
0
, and
t
0
>
t
α
,
n
−
1
when
H
a
:
µ>µ
0
.
For the null hypothesis
H
0
:
µ
1
=
µ
2
,
t
0
is computed as:
y
1
−
y
2
t
0
=
s
1
2
n
1
+
(6.9)
s
2
2
n
2
|
t
0
|
>
Similarly, the null hypothesis
H
0
:
µ
1
=
µ
2
would be rejected if
t
α
/2
,v
when
H
a
:
µ
1
=
µ
2
,
t
0
<
−
t
α
,
v
when
H
a
:
µ
1
<µ
2
, and
t
0
>
t
α
,
v
when
H
a
:
µ
1
>µ
2
, where
v
2.
The discussed examples of null hypotheses involved the testing of hypothe-
ses about one or more population means. Null hypotheses also can involve other
=
n
1
+
n
2
−
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