Geology Reference
In-Depth Information
From relation (1.335) the displacement field is found to have the components
1
C
x 1
ξ 1
Q 3
3 x 3 ( x 3
+ ξ 3 )
Q 2
=
u 1
,
(1.484)
1
ξ 2
Q 3
3 x 3 ( x 3
+ ξ 3 )
Q 2
C
x 2
u 2
=
,
(1.485)
Q 3 1
+ ξ 3 ) 2
Q 2
C
x 3
3 ( x 3
C
λ + μ
x 3
+ ξ 3
Q 3 ,
u 3
=
(1.486)
with derivatives
Q 3 1
1
ξ 1 ) 2
Q 2
ξ 1 ) 2
Q 2
u 1
x 1 =
C
3 ( x 1
3 C
x 3 ( x 3
+ ξ 3 )
Q 5
5 ( x 1
,
(1.487)
Q 3 1
1
ξ 2 ) 2
Q 2
ξ 2 ) 2
Q 2
u 2
C
3 ( x 2
3 C
x 3 ( x 3
+ ξ 3 )
Q 5
5 ( x 2
x 2 =
,
(1.488)
Q 3 1
1
3 ( x 3 + ξ 3 ) 2
Q 2
5 ( x 3 + ξ 3 ) 2
Q 2
u 3
x 3 =
C
3 C
x 3 ( x 3 + ξ 3 )
Q 5
Q 3 1
3 ( x 3 + ξ 3 ) 2
Q 2
6 C
x 3 ( x 3 + ξ 3 )
Q 5
C
λ + μ
1
.
(1.489)
Summing the derivatives, the cubical dilatation is found to be
Q 3 1
+ ξ 3 ) 2
Q 2
C
λ + μ
1
3 ( x 3
∇·
u
=−
.
(1.490)
This displacement field has the associated normal stresses
+ ξ 3 ) 2
Q 5
C μ
λ + μ
1
Q 3 +
3 C λ
λ + μ
( x 3
3 C x 3 ( x 3
+ ξ 3 )
Q 5
τ 11
=
1
3 C ( x 1 ξ 1 ) 2
Q 5
5 x 3 ( x 3 + ξ 3 )
Q 2
,
(1.491)
( x 3 + ξ 3 ) 2
Q 5
C μ
λ + μ
1
Q 3 +
3 C λ
λ + μ
3 C x 3 ( x 3 + ξ 3 )
Q 5
τ 22
=
1
ξ 2 ) 2
Q 5
3 C ( x 2
5 x 3 ( x 3
+ ξ 3 )
Q 2
,
(1.492)
Q 3 1
3
+ ξ 3 ) 2
Q 2
+ ξ 3 ) 2
Q 2
τ 33 =− μ
λ + μ
1
3 ( x 3
x 3 ( x 3
+ ξ 3 )
Q 5
5 ( x 3
,
(1.493)
 
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