Geology Reference
In-Depth Information
This solenoidal displacement field has the associated normal stresses
Q
3
1
−
ξ
1
)
2
Q
2
A
3
(
x
1
τ
11
=
−
,
(1.452)
Q
3
1
3
(
x
2
−
ξ
2
)
2
Q
2
A
τ
22
=
−
,
(1.453)
Q
3
1
+
ξ
3
)
2
Q
2
A
3
(
x
3
τ
33
=
−
,
(1.454)
and the associated shear stresses
3
A
(
x
1
−
ξ
1
)(
x
3
+
ξ
3
)
τ
13
=−
,
(1.455)
Q
5
3
A
(
x
2
−
ξ
2
)(
x
3
+
ξ
3
)
τ
23
=−
,
(1.456)
Q
5
3
A
(
x
1
−
ξ
1
)(
x
2
−
ξ
2
)
Q
5
τ
12
=−
.
(1.457)
This stress field generated by the Galerkin vector
G
1
produces a traction per unit
area, on a small sphere of radius
a
surrounding the image point, with components
F
1
=
τ
11
(
x
1
−
ξ
1
)
a
+
τ
12
(
x
2
−
ξ
2
)
a
+
τ
13
(
x
3
+
ξ
3
)
a
=−
2
A
(
x
1
−
ξ
1
)
a
4
,
(1.458)
=
τ
12
(
x
1
−
ξ
1
)
a
+
τ
22
(
x
2
−
ξ
2
)
a
+
τ
23
(
x
3
+
ξ
3
)
a
=−
2
A
(
x
2
−
ξ
2
)
a
4
F
2
,
(1.459)
=
τ
13
(
x
1
−
ξ
1
)
a
+
τ
23
(
x
2
−
ξ
2
)
a
+
τ
33
(
x
3
+
ξ
3
)
a
2
A
(
x
3
+
ξ
3
)
a
4
F
3
=−
.
(1.460)
The components of the total traction on the small sphere are then
a
2
2π
0
π
T
i
=
F
i
sinθ
d
θ
d
φ.
(1.461)
0
Thus,
T
1
=
0.
For the second Galerkin vector
G
2
,wehave
T
2
=
T
3
=
−
ξ
1
)
1
x
3
+
ξ
3
Q
3
∇
(
∇·
G
2
)
=
B
e
1
(
x
1
Q
(
Q
+
x
3
+
ξ
3
)
−
B
e
2
(
x
2
−
ξ
2
)
1
x
3
+
ξ
3
Q
3
+
+
ξ
3
)
−
Q
(
Q
+
x
3
B
e
3
2
(
x
3
+
ξ
3
)
2
Q
3
+
Q
−
,
(1.462)
and
B
e
3
2
2
G
2
=
∇
Q
.
(1.463)
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