Geology Reference
In-Depth Information
This solenoidal displacement field has the associated normal stresses
Q 3 1
ξ 1 ) 2
Q 2
A
3 ( x 1
τ 11 =
,
(1.452)
Q 3 1
3 ( x 2 ξ 2 ) 2
Q 2
A
τ 22
=
,
(1.453)
Q 3 1
+ ξ 3 ) 2
Q 2
A
3 ( x 3
τ 33 =
,
(1.454)
and the associated shear stresses
3 A ( x 1
ξ 1 )( x 3
+ ξ 3 )
τ 13 =−
,
(1.455)
Q 5
3 A ( x 2
ξ 2 )( x 3
+ ξ 3 )
τ 23
=−
,
(1.456)
Q 5
3 A ( x 1 ξ 1 )( x 2 ξ 2 )
Q 5
τ 12
=−
.
(1.457)
This stress field generated by the Galerkin vector G 1 produces a traction per unit
area, on a small sphere of radius a surrounding the image point, with components
F 1 = τ 11 ( x 1
ξ 1 )
a + τ 12 ( x 2
ξ 2 )
a + τ 13 ( x 3
+ ξ 3 )
a =−
2 A ( x 1
ξ 1 )
a 4
,
(1.458)
= τ 12 ( x 1
ξ 1 )
a + τ 22 ( x 2
ξ 2 )
a + τ 23 ( x 3
+ ξ 3 )
a =−
2 A ( x 2
ξ 2 )
a 4
F 2
,
(1.459)
= τ 13 ( x 1 ξ 1 )
a
+ τ 23 ( x 2 ξ 2 )
a
+ τ 33 ( x 3 + ξ 3 )
a
2 A ( x 3 + ξ 3 )
a 4
F 3
=−
.
(1.460)
The components of the total traction on the small sphere are then
a 2
0
π
T i
=
F i sinθ d θ d φ.
(1.461)
0
Thus, T 1 =
0.
For the second Galerkin vector G 2 ,wehave
T 2 =
T 3 =
ξ 1 ) 1
x 3
+ ξ 3
Q 3
(
∇·
G 2 )
=
B e 1 ( x 1
Q ( Q + x 3 + ξ 3 )
B e 2 ( x 2 ξ 2 )
1
x 3
+ ξ 3
Q 3
+
+ ξ 3 )
Q ( Q
+
x 3
B e 3 2
( x 3 + ξ 3 ) 2
Q 3
+
Q
,
(1.462)
and
B e 3 2
2 G 2 =
Q .
(1.463)
 
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