Geology Reference
In-Depth Information
1.4.2 Conditions of equilibrium
Let the body force per unit mass be f i . The total force acting on the volume
V
,
bounded by the surface
S
, vanishes in static equilibrium. Thus,
τ ji ν j d
S+
ρ f i d
V=
0,
(1.215)
S
V
with ρ representing the mass density.
In equilibrium, the moment about any point must also vanish. For the moment
about the origin, we have
ξ ijk x j τ lk ν l d
S+
ξ ijk x j ρ f k d
V=
0.
(1.216)
S
V
where ξ ijk is the alternating tensor.
The divergence theorem of Gauss allows us to convert the surface integrals to
volume integrals, giving, for force equilibrium,
∂τ ji
x j + ρ f i d V=
0,
(1.217)
V
and, for moment equilibrium,
ξ ijk
+ ρ x j f k d
x l x j τ lk
V
V
ξ ijk
x j ∂τ lk
x l + ρ f k d
(1.218)
=
τ jk
+
V=
0.
V
Since
V
is an arbitrary volume,
∂τ ji
x j =− ρ f i
(1.219)
and
ξ ijk
x j ∂τ lk
x l + ρ f k
τ jk +
= ξ ijk τ jk =
0.
(1.220)
The latter condition for moment equilibrium expands to three equations:
τ 23
τ 32
=
0,
τ 13
+ τ 31
=
0,τ 12
τ 21
=
0. Hence, moment equilibrium requires that
τ ij
= τ ji ,orthat the stress tensor is symmetric . The condition for force equilibrium
can then alternatively be written as
∂τ ij
x j =− ρ f i ,
(1.221)
referred to as the equation of equilibrium .
 
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