Geology Reference
In-Depth Information
Now let the unprimed quantities refer to the problem of a dislocation in an elastic
half-space and the primed quantities refer to the deformation caused by a point
force F i at the point x i in the elastic half-space. The surface integral on the left-
hand side of the reciprocal theorem vanishes, because t i is zero on the free surface
of the half-space and because it changes sign across the dislocation while u i is con-
tinuous there. The volume integral on the left-hand side of the reciprocal theorem
vanishes because there are no body forces in the dislocation problem. To evaluate
the surface integral on the right-hand side of the reciprocal theorem, let ν i be the
unit outward normal vector from the side of the dislocation with displacement u i .
The traction on this side of the dislocation is then t i = τ ij ν j . On the other side of the
dislocation, the normal vector is reversed and the displacement is u i
. The traction
on that side is then t i =− τ ij ν j . If the dislocation is
u i , the contribution
to the surface integral on the right-hand side of the reciprocal theorem from the
dislocation is
u i
Δ
u i =
S t i Δ
u i dS . Since t i vanishes on the free surface of the half-space
there is no contribution to the surface integral from there. If the point force F i is of
unit strength in the k -direction, generating a displacement field u i , the right-hand
side of the reciprocal theorem gives
u k ( x i )
t i Δ
=
u i dS ,
(9.2)
S
where the integral is over the surface of dislocation. By Hooke's law,
= ν j λ u k
.
u j
x i
u k
i
t i = τ ij ν j
i
j
x δ
+ μ
x j +
(9.3)
We are thus led to Volterra's formula,
u i λ u k
ν j dS .
u j
x i
u k
x δ
i
u k ( x i )
i
j
=
S Δ
+ μ
x j +
(9.4)
In this form of Volterra's formula, the displacement field is found by integrat-
ing derivatives of the point force solution over the fault surface, with the point
force located at the field point. If we denote the radius to the field point as r ,and
the radius to a point on the dislocation surface by r , then a point force in the k -
direction at r generates a displacement field u i ( r , r ) observed at r . With these
conventions, Volterra's formula takes the form
u i ( r ) λ u k
ν j dS . (9.5)
u j ( r , r )
x i
( r , r )
x
u k
i
( r , r )
x j +
i
j
u k ( r )
=
S Δ
δ
+ μ
Now introduce a second displacement field u k ( r , r ), which by our conventions is
the k th component of displacement produced by a unit point force in the i -direction
 
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