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X 3
n
F n
X 2
Δ
S
X 1
Figure 1.3 A small tetrahedron, in a stressed medium, cut out by the Cartesian
co-ordinate planes.
Aforce F acts on the outside of the small surface element, while an equal and
opposite force
F acts on the inside. The orientation of the surface element is
specified by its unit outward normal vector ν . To specify the state of stress in
the medium we must, in general, specify both F and ν . To do this, consider the
tetrahedron cut out by the Cartesian co-ordinate planes shown in Figure 1.3.
The faces of the tetrahedron orthogonal to the three co-ordinate directions have
areas
Δ
S 1 ,
Δ
S 2 and
Δ
S 3 , respectively, while the fourth face has area
Δ
S . Then,
Δ S 1 =−
cos(ν, x 1 )
Δ S ,
Δ
S 2 =−
cos(ν, x 2 )
Δ
S ,
(1.211)
Δ
S 3 =−
cos(ν, x 3 )
Δ
S ,
where an area is counted positive if it is on the side of the normal vector or co-
ordinate direction, negative otherwise, and where cos (ν, x i ) is the cosine of the
angle between ν and e i , the unit vector in the x i -direction. Let the force per unit
area acting on
S be F ν , that acting on
Δ
Δ
S i be F i . The sum of the surface forces
acting on the tetrahedron is therefore
F ν
F 3 cos(ν, x 3 )
F 1 cos(ν, x 1 )
F 2 cos(ν, x 2 )
Δ
S .
(1.212)
Body forces could also be acting on the medium enclosed by the tetrahedron.
Body forces are proportional to volume. Suppose L is a characteristic length of
the tetrahedron. Then, the surface forces are proportional to L 2 , the body forces
are proportional to L 3 .Ifwelet
Δ
S
0 with ν fixed, it is evident that the body
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