Geology Reference
In-Depth Information
ϑ
r
r
r
S
r
r
|
Figure 1.1 Small sphere of radius
=
, surrounding the source point
r
, as the source point and field point,
r
, approach coincidence.
R
=|
r
−
For
r
r
, the gradient of 1/
R
is
1
R
1
|
r
R
3
.
r
−
∇
=∇
=−
(1.170)
r
|
r
−
Taking the divergence yields
2
1
R
2
1
|
∇
=∇
r
−
r
|
2
x
1
x
3
2
x
1
2
2
x
2
x
2
2
2
x
3
−
+
−
+
−
3
2
3
R
3
=
=
−
0.
(1.171)
R
5
Now suppose the source point is close to the field point so that
R
is the very small
quantity . Surround the source point with a sphere of radius , as illustrated in
Figure 1.1.
Now take the Laplacian of expression (1.168). As the source point and field point
approach coincidence, the right side approaches
u
(
r
)
2
1
R
d
1
4π
∇·
V
.
−
∇
(1.172)
By the divergence theorem of Gauss, the volume integral throughout the small
sphere is the integral over its surface of the outward normal component of
∇
(1/
R
),
3
. The surface integral is then
3
2
equal to
4π. Thus, the volume
integral (1.168) is the general solution of the Poisson equation (1.163).
An arbitrary vector field
u
can then be broken into a lamellar part, determined
within a constant by the scalar potential φ given by (1.168), and a solenoidal part
−
/
−
/
×
4π
=−
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