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and
∂χ
∂ν
∂ν
z +
∂χ
∂μ
∂ν
z
2
χ
z 2 =
∂ν
∂ν
z
∂ν
∂μ
z
∂χ
∂μ
∂μ
z +
∂χ
∂ν
∂μ
z .
∂μ
∂μ
z
∂μ
∂ν
z
+
(6.38)
Di
ff
erentiation of (6.32) yields
ν ν
1 1
μ ν
1
2
2
2
R ∂ν
μ
∂ν
z =
R =
,
k ν
2 ,
(6.39)
2
2
2
ν
μ
μ
while di
ff
erentiation of (6.33) yields
μ ν
1 1
2
ν 1
2
2
R ∂μ
μ
∂μ
z =
μ
R =−
,
k ν
2 .
(6.40)
ν
2
μ
2
2
μ
With substitution from (6.39) and (6.40), and from (6.24) for R 2 ,itisfoundthat
R ∂χ
R
2
R
R
R 2
χ
z 2
+
ν ν
1 1
2
ν ν
1
νμ ν
1 1
2
ν
2
2
2
2
2
2
μ
μ
∂ν
2 ∂χ
∂ν
1
2 ∂χ
=
2
2
2
2
2
2
ν
μ
ν
μ
∂ν
ν
μ
ν
μ
∂μ
μ ν
1 2 1
2
μ 1
2
νμ ν
1 2 1
2
1
2
2
2
μ
∂μ
μ
2 ∂χ
μ
∂μ
μ
2 ∂χ
+
2
μ
2
2
μ
∂μ
2
μ
2
2
μ
∂ν
ν
ν
ν
ν
ν
1 2 1
ν
μ ν
1 2 1
2
2
2
2
2
2
2
μ
μ
∂ν
1
2 ∂χ
μ
∂ν
ν
2 ∂χ
+
+
ν
2
μ
2
ν
2
μ
∂ν
ν
2
μ
2
ν
2
μ
∂μ
ν
1 1
2
1
ν ν
1 2 1
2
2
2
2
2
2
2
ν
μ
μ
∂μ
μ
2 ∂χ
∂μ
μ
2 ∂χ
+
+
2
2
2
2
2
2
ν
μ
ν
μ
∂μ
ν
μ
ν
μ
∂ν
ν
1 1
∂ν
ν
1
2
2
μ
1 ∂χ
∂ν
+
∂μ
∂χ
∂μ
2
2
=
μ
.
(6.41)
ν
2
μ
2
In the auxiliary prolate spheroidal co-ordinates, the governing Laplace form of the
Poincare equation then becomes
ν
∂ν
ν
1
1 1
2
2
μ
1 ∂χ
∂ν
∂μ
∂χ
∂μ
2
2
m 2
+
μ
χ =
0.
(6.42)
2
2
ν
μ
If we take χ =
f (ν)g(μ)exp i ( m φ + ω t ), the variables separate, giving
ν
1
m 2
m 2
1
f
d
d ν
1
df
d ν
1
g
d
d μ
d g
d μ
2
2
1 =−
μ
+
2 =
n ( n
+
1), (6.43)
ν
2
1
μ
 
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