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where
B
T
is the inverse of
A
with elements
b
ij
. Thus, the transformation (1.139) is
expressible as
τ
i
j
=
|
A
|
b
ij
τ
.
(1.141)
Writing out the implied summation in expression (1.34), we have, by the familiar
chain rule for partial derivatives,
∂
u
j
=
∂
u
i
∂
u
i
∂
u
1
∂
u
1
∂
u
j
+
∂
u
i
∂
u
2
∂
u
2
∂
u
j
+
∂
u
i
∂
u
3
∂
u
3
i
j
.
∂
u
j
=
δ
(1.142)
Choosing
b
kj
=
∂
u
k
∂
u
j
,
(1.143)
relation (1.142) can be written as
i
j
,
a
ki
b
kj
=
δ
(1.144)
or, in matrix notation, as
A
T
B
B
T
A
=
=
I
,
(1.145)
where
I
is the unit matrix, confirming the choice (1.143) of the elements of
B
T
A
−
1
. Taking the determinant of both sides of (1.145),
=
|
A
||
B
|=
1,
(1.146)
A
T
B
T
since
|
|=|
A
|
and
|
|=|
B
|
. The transformation (1.141) then takes the form
j
J
u
1
∂
u
i
∂
u
j
τ
,
u
2
,
u
3
1
τ
i
j
=
b
ij
τ
=
.
(1.147)
|
B
|
u
1
,
u
2
,
u
3
j
transforms as a contravariant vector, except that in the transforma-
tion it is divided by the Jacobian. Thus, it is not a true tensor but is a
tensor density
.
The quantity τ
1.1.9 Cartesian tensors
Tensor analysis is considerably simplified when carried out in Cartesian co-ordinate
systems. Continuing to confine our attention to right-handed systems, a point
P
(
u
1
,
u
2
,
u
3
) is at Cartesian co-ordinates
u
1
x
1
,
u
2
x
2
,
u
3
x
3
.The
unit vectors
e
1
,
e
2
,
e
3
in the directions of increasing
x
1
,
x
2
,
x
3
form a right-handed
system with metrical coe
=
x
=
=
y
=
=
z
=
1. Then, the distinction between
covariant and contravariant tensors vanishes as does the distinction between tensor
and physical components. In addition, both the unitary base vectors and the recip-
rocal unitary base vectors become identical to the unit vectors
e
1
,
e
2
,
e
3
.
cients
h
1
=
h
2
=
h
3
=
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