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d
r 0 ρ( r 0 ) f +
7 κ dr 0
¯ρ( r 0 ) m ( r 0 ) 10
9
9 r 0 f
9
4
2
7 ff +
+
f
+
3 ¯ρ( r 0 ) f
r 0 f 2
2
1
2
21
35
47
4
2 r 0 f +
4 r 0 ff +
f 2
3 r 0 κ +
+
+
+
5
6 ¯ρ( r 0 ) m ( r 0 )
=−
(5.160)
and
d
r 0 ρ( r 0 ) r 0 κ
1
dr 0
r 0
(5.161)
¯ρ( r 0 ) r 0 f 2
16κ
1
12 r 0
2 r 0 ff
4 r 0 κ
+
+
=
0.
Di
ff
erentiation of the mean density expression (5.156) yields
d ¯ρ
dr 0 =−
3 ρ
r 0
(1
ρ/¯ρ).
(5.162)
Di
erentiation of expression (5.160) with respect to r 0 , and substitution from rela-
tion (5.162), gives
ff
ρ( r 0 ) f +
7 κ
¯ρ( r 0 ) m ( r 0 ) 12
9
9 r 0 f
9
4
2
7 ff +
f +
+
3 ¯ρ( r 0 ) 1
2 r 0 f 2
r 0 f f
2 3 f +
r 0 f +
2
2
21
+
(5.163)
4 r 0 f 2
ff
35
47
3 κ +
r 0 κ +
r 0 ff +
2 ff +
+
+
+
ρ/¯ρ) f
r 0 f 2
2
r 0 ¯ρ(1
1
2
21
35
47
4
2 r 0 f +
4 r 0 ff +
f 2
3 r 0 κ +
+
+
+
+
=
0.
2 r 0 / GM i
Note that the product ¯ρ( r 0 ) m ( r 0 ) is independent of r 0 ,since m ( r 0 )
r 0 ¯ρ( r 0 )/3, hence ¯ρ( r 0 ) m ( r 0 )
2
and M i
=
=
3
Ω
/4π G .
erentiating (5.161) with respect to r 0 , and again substituting from
(5.162), produces
Similarly, di
ff
 
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