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d
r
0
ρ(
r
0
)
f
+
7
κ
dr
0
¯ρ(
r
0
)
m
(
r
0
)
10
9
9
r
0
f
9
4
2
7
ff
+
+
f
+
3
¯ρ(
r
0
)
f
r
0
f
2
2
1
2
21
35
47
4
2
r
0
f
+
4
r
0
ff
+
f
2
3
r
0
κ
+
−
+
+
+
6κ
5
6
¯ρ(
r
0
)
m
(
r
0
)
=−
(5.160)
and
d
r
0
ρ(
r
0
)
r
0
κ
−
1
2κ
dr
0
r
0
(5.161)
¯ρ(
r
0
)
r
0
f
2
16κ
1
12
r
0
2
r
0
ff
−
4
r
0
κ
−
+
+
=
0.
Di
ff
erentiation of the mean density expression (5.156) yields
d
¯ρ
dr
0
=−
3
ρ
r
0
(1
−
ρ/¯ρ).
(5.162)
Di
erentiation of expression (5.160) with respect to
r
0
, and substitution from rela-
tion (5.162), gives
ff
−
ρ(
r
0
)
f
+
7
κ
¯ρ(
r
0
)
m
(
r
0
)
12
9
9
r
0
f
9
4
2
7
ff
+
f
+
+
3
¯ρ(
r
0
)
1
2
r
0
f
2
r
0
f
f
2
3
f
+
r
0
f
+
2
2
21
−
+
(5.163)
6κ
4
r
0
f
2
ff
35
47
3
κ
+
r
0
κ
+
r
0
ff
+
2
ff
+
+
+
+
−
ρ/¯ρ)
f
r
0
f
2
2
r
0
¯ρ(1
1
2
21
35
47
4
2
r
0
f
+
4
r
0
ff
+
f
2
3
r
0
κ
+
+
+
+
+
6κ
=
0.
2
r
0
/
GM
i
Note that the product ¯ρ(
r
0
)
m
(
r
0
) is independent of
r
0
,since
m
(
r
0
)
=Ω
4π
r
0
¯ρ(
r
0
)/3, hence ¯ρ(
r
0
)
m
(
r
0
)
2
and
M
i
=
=
3
Ω
/4π
G
.
erentiating (5.161) with respect to
r
0
, and again substituting from
(5.162), produces
Similarly, di
ff
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