Geology Reference
In-Depth Information
Now,
sin (
β
−
γ
)
cos (β
−
γ)
tan (β
−
γ)
=
sinβcosγ
−
cosβsinγ
=
cosβcosγ
+
sinβsinγ
tanβ
−
tanγ
=
tanβtanγ
,
(4.91)
1
+
and hence,
tanβ
−
tanγ
Ω
tanβtanγ
=
Ω+
σ
0
)
tanβ,
(4.92)
1
+
(
on choosing the positive root. This gives
1
Ω
Ω
Ω+
σ
0
tanβ
Ω+
σ
0
tan
2
tanβ
−
tanγ
+
β
=
(4.93)
or
−
Ω
1
tan
γ
tanβ
=
σ
0
σ
0
+Ω
Ω+
σ
0
β
=
β
.
(4.94)
+
Ω
sec
2
tan
2
1
Ω+
σ
0
The quantities β, σ
0
,
are all constants of the motion, therefore γ is also a con-
stant of the motion. The angular velocity vector
ω
then describes a small cone (the
herpolhode) about the invariable axis
L
with semi-apex angle γ.
Of interest is the rate of progression of
ω
about
L
.Letξ measure the angular
position of
ω
in its path about
L
. In time δ
t
the increase in ξ is δξ. The component
of
ω
normal to
L
is
Ω
sinγ. This acts as a radius vector moving through the angle
δξ in time δ
t
to produce the change δ
ω
in time δ
t
. Then,
|
ω
|
L
×
ω
δ
ω
=
δξ
|
ω
|
sinγ
=
δξ
·
(4.95)
|
L
|
and the time derivatives of
ω
and ξ are related by
L
×
ω
˙
ω
=
ξ
.
(4.96)
|
L
|
We also have that
ω
=Ω
m
1
e
1
+Ω
m
2
e
2
.
(4.97)
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