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e 1 / h 1 e 2 / h 2 e 3 / h 3
V 1 / h 1 V 2 / h 2 V 3 / h 3
W 1 / h 1 W 2 / h 2 W 3 / h 3
V × W = h 1 h 2 h 3
e 1 e 2 e 3
V 1 V 2 V 3
W 1 W 2 W 3
=
.
(1.111)
The cross product takes its familiar form in all orthogonal co-ordinate systems.
From this, it follows that the triple scalar product (A.1) can be written in the form
of a determinant as
a 1 a 2 a 3
b 1 b 2 b 3
c 1
a
·
( b
×
c )
=
.
(1.112)
c 2
c 3
Substitution in formula (1.79) for the curl gives
h 1 e 1
h 2 e 2
h 3 e 3
1
h 1 h 2 h 3
∂/∂ u 1
∂/∂ u 2
∂/∂ u 3
∇×
V
=
,
(1.113)
h 1 V 1
h 2 V 2
h 3 V 3
while substitution in formula (1.90) for the divergence gives
u 1 ( h 2 h 3 V 1 )
u 3 ( h 1 h 2 V 3 )
1
h 1 h 2 h 3
+
+
∇· V =
u 2 ( h 3 h 1 V 2 )
.
(1.114)
The gradient (1.96) of a scalar function φ becomes
h 1 ∂φ
1
h 2 ∂φ
1
h 3 ∂φ
1
φ =
u 1 e 1 +
u 2 e 2 +
u 3 e 3 ,
(1.115)
b j by 1/ h i .
The Laplacian (1.98) of φ, in an orthogonal system, takes the form
ij
b i
on replacing g
=
·
u 1 h 2 h 3
u 1
u 2 h 3 h 1
u 2
u 3 h 1 h 2
u 3
1
h 1 h 2 h 3
h 1 ∂φ
h 2 ∂φ
h 3 ∂φ
2
φ =
+
+
. (1.116)
In Cartesian co-ordinates, the vector identity (A.14),
2 V ,
∇×
(
∇×
V )
=∇
(
∇·
V )
−∇
(1.117)
is easily established. In Cartesian co-ordinates the unit vectors are independent of
position, and the operator
2 V can be interpreted as the Laplacian operating on
each of the Cartesian components of V ,or
2 V
2 V j .
=
e j
(1.118)
 
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