Geology Reference
In-Depth Information
required for the calculation of k 4 . Thus,
h
2
h
h f
1
2!
k 3
∂y
1
2
k 3
∂y
k 3 f
∂y
r +
f
=
r +
r +
h 2
2 f
r +
2 f
r ∂y +
2 f
∂y
1
2
2 hk 3
k 3
=
2
1
2
h 2
2 h hf
2 Df
2 f
r 2 +
h 2
2 f
r ∂y
=
+
r = r i +
h 2 f 2
h 3 fDf
2 f
∂y
O h 4
+
+
2
r = r i +
h 2
2 Df
h 3
2 f
r ∂y +
2 f
∂y
O h 4
f
2 D 2 f
=
+
2
r = r i +
h 2
h 3
2 Df Df y
O h 4 ,
2 D 2 f
=
+
(3.291)
again using (3.268) and the identity
2 f
r ∂y +
2 f
∂y
f i
2 =
Df y .
(3.292)
Again,
h
3
h
h 2
2 f
r 2 +
2 f
r ∂y +
2 f
∂y
1
3!
k 3
∂y
1
6
k 3
∂y
2 hk 3
k 3
r +
f
=
r +
2
r = r i +
h 3
6
r +
2 f
r 2 +
2 f
r ∂y +
2 f
∂y
f
∂y
2 f
f 2
O h 4
=
2
6 D 3 f r = r i +
h 3
O h 4 ,
=
(3.293)
using (3.270). From (3.290) with substitution from (3.289), (3.291) and (3.293),
we find that
k 4 =
hf ( r i +
h ,y i +
k 3 )
hf
2 D 2 f
f y Df
h 3
h 2 Df
=
+
+
+
r = r i +
D 3 f
h 4
6
3
3
O h 5 .
4 f y D 2 f
2 f 2
+
+
+
y Df
+
3 Df Df y
(3.294)
 
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