Geology Reference
In-Depth Information
where
k
1
=
hf
(
r
i
,y
i
),
k
2
=
hf
r
i
+
h
2
,y
i
+
k
1
2
,
hf
r
i
(3.282)
h
2
,y
i
k
2
2
k
3
=
+
+
,
k
4
=
hf
(
r
i
+
h
,y
i
+
k
3
).
Since
k
1
=
hf
i
,Taylorexpansionintwovariablesgives
hf
r
i
+
h
2
,y
i
+
k
1
2
k
2
=
48
D
3
f
r
=
r
i
+
O
h
5
.
hf
+
h
2
2
Df
+
h
3
h
4
8
D
2
f
+
=
(3.283)
This expression for
k
2
can be used to develop the expansion,
f
r
i
⎩
h
2
h
2
,y
i
k
2
2
h
2
∂
f
k
2
2
∂
f
1
2!
2
∂
k
2
2
∂
+
+
=
f
(
r
,y)
+
∂
r
+
∂y
+
∂
r
+
f
∂y
⎭
r
=
r
i
,
h
3
1
3!
2
∂
k
2
2
∂
+
∂
r
+
+···
f
(3.284)
∂y
required for the calculation of
k
3
. Thus,
h
2
h
h
1
2!
2
∂
k
2
2
∂
1
2
2
∂
k
2
2
∂
2
∂
f
k
2
2
∂
f
∂
r
+
f
=
∂
r
+
∂
r
+
∂y
∂y
∂y
h
2
∂
2
f
∂
r
2
+
2
f
∂
r
∂y
+
2
f
∂y
1
8
2
hk
2
∂
k
2
∂
=
2
1
8
h
2
∂
2
h
hf
2
Df
∂
2
f
∂
r
2
+
h
2
2
f
∂
r
∂y
=
+
r
=
r
i
+
h
2
f
2
h
3
fDf
∂
2
f
∂y
O
h
4
.
+
+
(3.285)
2
Then,
r
=
r
i
+
h
2
h
2
8
Df
∂
h
3
2
f
∂
r
∂y
+
2
f
∂y
O
h
4
1
2!
2
∂
k
2
2
∂
f
∂
8
D
2
f
∂
r
+
f
=
+
2
∂y
r
=
r
i
+
h
2
h
3
8
DfDf
y
O
h
4
,
8
D
2
f
=
+
(3.286)
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