Geology Reference
In-Depth Information
A 1,4 , A 2,3 , A 3,4 , A 4,3 are given by the system (3.139) in terms of A 1,2 , A 3,2 , A 6,2 ,
A 5,3 for ν =
4, η =
3. In turn, A 5,5 , A 6,4 are given by the system (3.143) in terms of
A 1,4 , A 3,4 for ν =
4. For the regular solution generated by the free constant
A 4,1 , the extra terms A 1,6 , A 2,5 , A 3,6 , A 4,5 are given by the system (3.139) in terms
of A 1,4 , A 3,4 , A 6,4 , A 5,5 for ν =
5, η =
6, η =
5. In turn, the extra terms A 5,7 , A 6,6 are given
by the system (3.143) in terms of A 1,6 , A 3,6 for ν =
7, η =
6.
0, near the geocentre, the fourth-order system governing the radial spher-
oidal deformations, (3.110) through (3.113), takes the form
For n
=
d y 1
dr =−
2 λ r y 1
+ βy 2 ,
(3.237)
r 2
ρ 0 +
2
d y 2
dr =
2 δ
4 μ r y 2 ρ 0 y 6 ω
2
2
Ω
+
y 1
ρ 0 y 1 ,
(3.238)
d y 5
dr =
G ρ 0 y 1 + y 6 ,
(3.239)
d y 6
dr =−
2
r y 6 .
(3.240)
Substitution of the power series expansions (3.138) in these equations, and equat-
ing coe
cients of like powers of the radius, yields the systems
= ρ 0
,
0
2λβ +
1
+ η β
A 1,ν
A 2,ν 1
+ ω
2 A 1,ν 2
2
4μβ + η
+
2
Ω
A 6,ν 2
(3.241)
and
=
,
1
+ η
1
02
A 5,ν
A 6,ν 1
G ρ 0 A 1,ν 1
0
(3.242)
+ η
for ν =
0,1,2,....The first system has a singular coe
cient matrix for η =−
3and
for η =
0, while the coe
cient matrix of the second system is singular for η =−
2
and for η =−
1.
For ν =
0, η = α
1, the system (3.241) gives (α +
2λβ) A 1,0
=−
A 1,0
=
0or
A 1,0
=
0. The system (3.242) gives α A 5,0
=
0or A 5,0
=
0, except for α =
0.
1, η = α, the system (3.241) is homogeneous and has a non-trivial solu-
tion only for η = α =
For ν =
0. The solution is (3λ +
2μ) A 1,1
=
A 2,0 . The system (3.242) is
homogeneous and non-singular for α = η =
0. No further
singular values of η are encountered in either system with increasing ν.
For ν =
0, giving A 5,1
=
A 6,0
=
2, we have η = α +
1
=
1forα =
0, so the system (3.241) is homogen-
eous and non-singular, implying that A 1,2
=
A 2,1
=
0. The system (3.242) is also
non-singular, giving A 5,2
=
G ρ 0 A 1,1 and A 6,1
=
0.
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