Geology Reference
In-Depth Information
Taking complex conjugates of both sides and using the Hermitian property of the
autocorrelations gives
⎝
⎠
⎝
⎠
⎝
⎠
Δ
∗
2
0
P
2
φ
ff
(0) φ
ff
(
−
1) φ
ff
(
−
2)
0
γ
∗
1,1
1
φ
ff
(1) φ
ff
(0)
φ
ff
(
−
1)
=
.
(2.487)
φ
ff
(2) φ
ff
(1)
φ
ff
(0)
Now, we multiply the system (2.487) by the parameter γ
2,2
and add it to the system
(2.485) to get
⎝
⎠
⎝
⎝
⎠
⎝
⎠
⎠
φ
ff
(0) φ
ff
(
−
1) φ
ff
(
−
2)
1
γ
1,1
0
0
γ
∗
1,1
1
φ
ff
(1) φ
ff
(0)
φ
ff
(
−
1)
+
γ
2,2
φ
ff
(2) φ
ff
(1)
φ
ff
(0)
⎝
⎝
⎠
⎝
⎠
⎠
Δ
∗
2
0
P
2
P
2
0
Δ
=
+
γ
2,2
.
(2.488)
2
If this system is to match the prediction error equations (2.80) for
N
=
2,
Δ
∗
2
=
P
2
+
γ
2,2
P
3
,
(2.489)
+
γ
2,2
γ
∗
1,1
=
γ
1,2
,
γ
1,1
(2.490)
Δ
+
γ
2,2
P
2
=
0.
(2.491)
2
γ
2,2
is then the only free parameter left to be determined. From equation (2.491),
Δ
2
=−
γ
2,2
P
2
. Then, from equation (2.489),
1
−
γ
2,2
γ
∗
2,2
P
2
.
P
3
=
(2.492)
The third equation of the system (2.488) yields
φ
ff
(2)
=−
γ
1,2
φ
ff
(1)
−
γ
2,2
φ
ff
(0).
(2.493)
Once again we take
P
3
to be given by the average of the forward and backward
prediction errors,
F
j
+
2,2
=
f
j
+
2
+
γ
1,2
f
j
+
1
+
γ
2,2
f
j
,
j
=
1,...,
M
−
2
γ
1,1
+
γ
2,2
γ
∗
1,1
f
j
+
1
=
f
j
+
2
+
+
γ
2,2
f
j
F
j
+
2,1
B
=
+
γ
2,2
j
,1
,
(2.494)
j
,2
f
j
+
γ
∗
1,2
f
j
+
1
+
γ
∗
2,2
f
j
+
2
,
=
j
=
1,...,
M
−
2
γ
∗
1,1
+
γ
∗
2,2
γ
1,1
f
j
+
1
+
γ
∗
2,2
f
j
+
2
=
f
j
+
B
j
,1
+
γ
∗
2,2
F
=
j
+
2,1
.
(2.495)
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