Geology Reference
In-Depth Information
Taking complex conjugates of both sides and using the Hermitian property of the
autocorrelations gives
Δ 2
0
P 2
φ ff (0) φ ff (
1) φ ff (
2)
0
γ 1,1
1
φ ff (1) φ ff (0)
φ ff (
1)
=
.
(2.487)
φ ff (2) φ ff (1)
φ ff (0)
Now, we multiply the system (2.487) by the parameter γ 2,2 and add it to the system
(2.485) to get
φ ff (0) φ ff (
1) φ ff (
2)
1
γ 1,1
0
0
γ 1,1
1
φ ff (1) φ ff (0)
φ ff (
1)
+ γ 2,2
φ ff (2) φ ff (1)
φ ff (0)
Δ 2
0
P 2
P 2
0
Δ
=
+ γ 2,2
.
(2.488)
2
If this system is to match the prediction error equations (2.80) for N
=
2,
Δ 2 =
P 2
+ γ 2,2
P 3 ,
(2.489)
+ γ 2,2 γ 1,1 = γ 1,2 ,
γ 1,1
(2.490)
Δ
+ γ 2,2 P 2
=
0.
(2.491)
2
γ 2,2 is then the only free parameter left to be determined. From equation (2.491),
Δ 2 =− γ 2,2 P 2 . Then, from equation (2.489),
1
γ 2,2 γ 2,2 P 2 .
P 3
=
(2.492)
The third equation of the system (2.488) yields
φ ff (2)
=− γ 1,2 φ ff (1)
γ 2,2 φ ff (0).
(2.493)
Once again we take P 3 to be given by the average of the forward and backward
prediction errors,
F
j + 2,2
=
f j + 2
+ γ 1,2 f j + 1
+ γ 2,2 f j ,
j
=
1,..., M
2
γ 1,1
+ γ 2,2 γ 1,1 f j + 1
=
f j + 2
+
+ γ 2,2 f j
F
j + 2,1
B
=
+ γ 2,2
j ,1 ,
(2.494)
j ,2
f j + γ 1,2 f j + 1 + γ 2,2 f j + 2 ,
=
j
=
1,..., M
2
γ 1,1 + γ 2,2 γ 1,1 f j + 1
+ γ 2,2 f j + 2
=
f j
+
B
j ,1
+ γ 2,2
F
=
j + 2,1 .
(2.495)
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