Geology Reference
In-Depth Information
Adding i
×
(2.479) to (2.478) gives
f j f j + 1 + γ 1,1 f j
f j + 1 f j + γ 1,1 f j + 1
M 1
+
=
0.
(2.480)
j = 1
Solving for the value of γ 1,1 that minimises P 2 ,weget
M 1
M 1
f j + 1 f j
f j + 1 f j + 1 +
f j f j
γ 1,1
=−
2
j = 1
j = 1
2
M
1
M
1
j ,0
j + 1,0
j ,0
2
F
B
F
B
=−
2
j + 1,0
+
,
(2.481)
j
=
1
j
=
1
if we interpret the forward prediction error sequence as
F
j + 1,0
=
f j + 1 ,
(2.482)
and the backward prediction error sequence as
B
j ,0
=
f j
(2.483)
for N
0 is just the unit impulse and
the two prediction error sequences are both just the original data sequence itself.
For this value of γ 1,1 , equations (2.473) give the recurrence relations
=
0. In fact, the prediction error filter for N
=
1
γ 1,1 γ 1,1 P 1 .
φ ff (1)
=− γ 1,1 φ ff (0)
and P 2 =
(2.484)
The next step is reminiscent of the Levinson algorithm (Section 2.2.3). We begin
with the system of equations
φ ff (0) φ ff (
1) φ ff (
2)
1
γ 1,1
0
P 2
0
Δ 2
φ ff ( 1 ) φ ff ( 0 )
φ ff (
1 )
=
,
(2.485)
φ ff ( 2 ) φ ff ( 1 )
φ ff ( 0 )
where
2 is defined by the third equation, and the first two equations are those
(2.473) for N
Δ
=
1. Reversing the order of equations and unknowns yields the
system
φ ff (0)
φ ff (1)
φ ff (2)
0
γ 1,1
1
Δ
2
φ ff (
1 ) φ ff ( 0 )
φ ff ( 1 )
=
0
P 2
.
(2.486)
φ ff (
2 ) φ ff (
1 ) φ ff ( 0 )
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