Geology Reference
In-Depth Information
Again, using the shifting theorem and that the Fourier transform of a convolution is
the product of the transforms (2.269), the Fourier integral representation of J m (τ)
is expressed as
exp ( i f τ) exp i f ( b n + m
b n ) W 2 ( f ) df .
J m (τ)
=
(2.382)
−∞
For τ =
0, we then have that
exp i f ( b n + m
b n ) W 2 ( f ) df
J m (0)
=
J m
=
−∞
M /2
M /2 w( t )w( t m Δ s ) dt .
=
(2.383)
Substituting in expression (2.380), we obtain for the covariance,
cov S gg, n ( f ),
S gg, n + m ( f )
J m
I 2 S 2
S 2
=
gg ( f )
=
gg ( f )ρ( m ),
(2.384)
J m / I 2 . Since J 0
where ρ( m )
=
=
I ,
cov S gg, n ( f ),
S gg, n ( f )
var S gg, n ( f )
S 2
=
=
gg ( f ).
(2.385)
Expression (2.364) for the variance of the final spectral density estimate, taken as
an average of the sample spectral density estimates over κ overlapping segments of
length M ,thenbecomes
var S gg ( f )
κ ρ( m ) .
2 κ 1
S 2
gg ( f )
κ
κ
m
=
1
+
(2.386)
m =
1
This formula was quoted and used by Welch (1967) in an analysis using Bartlett
windows with 50% overlap.
Instead, we have adopted the Parzen window (2.284), and we use 75% over-
lap. The Parzen time window is a piecewise cubic, and the integrals, J m , can be
evaluated analytically. We find that
151
560 M ,
397
40 J 2 ,
3
224 M ,
1
120 J 2 ,
J 0 =
I
=
J 1 =
J 2 =
J 3 =
(2.387)
giving,
397
40 ·
2
3
224 ·
560
151
ρ(1)
=
=
0.2430131,
3
224 ·
2
560
151
ρ(2)
=
=
0.0024670,
(2.388)
1
120 ·
2
3
224 ·
560
151
ρ(3)
=
=
0.0000002,
ρ(1)
+ ρ(2)
+ ρ(3)
=
0.2454803.
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