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2 N +1
-4 f N
-2 f N
0
2 f N
4 f N
f
Figure 2.12 The Fourier transform of the finite Dirac comb with 21 sample points
and unit sample interval
t . The transform is periodic in frequency with period
equal to twice the Nyquist frequency, 2 f N =
Δ
1/ Δ
t .
where T
t is the record length. A graph of the Fourier transform of the
finite Dirac comb sampler is shown in Figure 2.12 for 2 N
=
(2 N
+
1)
Δ
21 sample points
with unit sample interval. It is periodic in frequency, with period equal to twice the
Nyquist frequency ,2 f N
+
1
=
t .
The Fourier transform of the finite Dirac comb sampler (2.290), illustrated in
Figure 2.12, requires some interpretation. The numerator has zeros at fT
=
1/ Δ
=
0, ±
1,
±
2,....The denominator has zeros at f
Δ
t
=
0, ±
1, ±
2,...,orat f
=
0, ±
1/ Δ
t ,
±
2/ Δ
t ,....Consider the value of the transform at f
=
n / Δ
t , a zero of the denom-
inator. Since sin[π( n / Δ
t ) T ]
=
sin[(2 N
+
1) n π]
=
0, the numerator has a zero there
too. By l'Hopital's rule,
sin π f (2 N
t
+
1)
Δ
li m
sin ( π f
Δ
t )
n
Δ t
f
1) cos π f (2 N
t
+
1)
Δ
=
li m
(2 N
+
cos ( π f
Δ
t )
n
Δ t
f
1) n (2 N + 1)
(
1) (
=
(2 N
+
1) n
1) 2 Nn ( 2 N
=
+
1 )
=
+
(
2 N
1.
(2.291)
Both numerator and denominator have zeros and are changing sign at the points
f
t . Their quotient is therefore not changing sign at these points. The denom-
inator is a much weaker function of frequency than the numerator and, thus, near
=
n / Δ
 
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