Digital Signal Processing Reference
In-Depth Information
N
denote an image. Any particular pixel of
X
is written as
X
n
,
m
.The
discrete directional derivatives on
X
are defined pixel-wise as
N
×
Let
X
∈
C
(
X
x
)
=
X
n
,
m
−
X
n
−
1
,
m
n
,
m
(
X
y
)
n
,
m
=
X
n
,
m
−
X
n
,
m
−
1
.
N
×
N
×
2
Based on these, the discrete gradient operator
∇
where
∇
X
∈
C
is defined as
(
∇
X
)
n
,
m
=((
X
x
)
n
,
m
,
(
X
y
)
n
,
m
)
.
From these operators, one can define the discrete total-variational operator
TV
or
|
∇
|
on
X
as
(
TV
[
X
])
n
,
m
=(
|
∇
|
(
X
))
n
,
m
=
|
(
)
|
2
+
|
(
)
|
2
,
X
x
X
y
(3.1)
n
,
m
n
,
m
from which one can also define the total-variation seminorm of
X
as
X
TV
=
TV
(
X
)
1
.
It is said that
X
is
K
-sparse in gradient (or in the total-variational sense) if
|
∇
|
(
K
.
The objective is to recover an image
X
that is
K
-sparse in gradients from a set of
X
)
0
=
N
2
M
Fourier measurements. To that end, define a set
Ω
of
M
two-dimensional
frequencies
ω
k
=(
ω
x
,
k
,
ω
y
,
k
)
,1
≤
k
≤
M
chosen according to a particular sampling
2
.Let
pattern from
{
0
,
1
,···,
N
−
1
}
F
denote the two-dimensional DFT of
X
m
=
0
X
(
n
,
m
)
ex p
−
2π
i
n
ω
x
N
−
N
−
1
n
=
0
1
m
ω
y
N
F
(
ω
x
,
ω
y
)=
N
,
F
−
1
and
its inverse
ω
y
=
0
F
(
ω
x
,
ω
y
)
ex p
2π
i
n
ω
N
,
1
ω
x
=
0
N
−
N
−
1
1
N
2
m
ω
y
F
−
1
{F
(
ω
x
,
ω
y
)
}
=
X
(
n
,
m
)=
.
N
N
×
N
M
Next define the operator
F
Ω
:
C
→
C
as
(
F
Ω
X
)
k
=(
F
X
)
ω
k
(3.2)
F
Ω
i.e. Fourier transform operator restricted to
will represent its conjugate
adjoint. Equipped with the above notation, the main problem considered in [108]
can be formally stated as follows:
Ω
.
N
2
frequencies and Fourier observations of a
K
-sparse in
3.1.
Given a set
Ω
of
M
gradient image
X
given by
F
Ω
X
, how can one estimate
X
accurately and efficiently?
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