Biomedical Engineering Reference
In-Depth Information
J = kn
ρ
(x)
x
β
x 2
x 1
x u
x 0
FIGURE 3.3 The prescription for deriving Kramers rate of escape, k . The distribution of
particles in the well at x o provide a source, while the location outside the barrier x u acts as
a sink. Therefore, a steady flow of particles, or flux J , is passing over the barrier. The flux is
defined as the number of particles available n times rate of escape. Thus, estimating the flux
and integrating over the distribution of particles in the well provides the transition rate (see
discussion in text).
in the well provide a constant flux of particles over the barrier (steady-state condi-
tions). To the far left, the steeply rising energy is essentially a reflecting boundary.
To the right, after particles pass over the barrier and reach x u , they are completely
unbound and carried away from the potential indefinitely. Therefore, we define x u as
an absorbing boundary with ρ
0. To calculate the flux over the barrier, we look
to integrate over x o to x u . Multiplying both sides of Equation 3.9 by an integrating
factor exp
(
x u
)
(
U
(
x
) /
k B T
)
,wehave
U (
∂ρ
(
x
)
ρ
(
x
)
x
)
η J
k B T e U ( x ) / k B T
e U ( x ) / k B T
e U ( x ) / k B T
+
=
(3.10)
x
k B T
ρ
e U ( x ) / k B T
d
d x
η J
k B T e U ( x ) / k B T
(
x
)
=
(3.11)
Where we have exploited the fact that the left side of Equation 3.10 is just the chain
rule derivative of ρ
(
x
)
exp
(
U
(
x
) /
k B T
)
. Upon integration, and noting that ρ
(
x u
)=
0,
we have
e U ( x 0 ) / k B T
(
)
k B T
η
ρ
x 0
J
=
(3.12)
x u
x 0
e U
(
x
) /
k B T d x
Now the flux J is the steady flow of particles moving from a source, the well, over
the barrier and into a sink (or carried away). To determine the actual rate k of par-
ticles escaping per unit time, we recognize that the flux is the product of the rate
with the number of particles available to escape, J
kn . Therefore, we need to find
how the particle concentration changes along x .Define n as the number of particles
in the well. Near the bottom of the well, around x 0 ,theflux is nearly zero and we
=
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