Environmental Engineering Reference
In-Depth Information
Using constants for 1-inch Berl saddles:
97(250)
0
.
36
(1
3)
0
.
5
(4000)
0
.
4
H
G
=
1
.
.
/
=
0
.
6ft
.
10
−
3
(592)
0
.
5
4000
2
0
.
28
H
L
=
5
.
9
×
.
5
=
1
.
13 ft
.
mV
L
H
OG
=
H
G
+
H
L
26(250)
4000
=
0
.
6ft
+
(1
.
13 ft)
=
2
.
44 ft
.
mV
L
A
=
26(250)
4000
=
=
1
.
63
.
y
A
out
=
x
A
in
=
0
mx
A
in
=
0
ln
A
y
A
in
−
−
1
mx
A
in
1
A
+
y
A
out
−
A
mx
A
in
N
OG
=
A
−
1
A
0
0
.
.
63
02
1
+
1
.
63
0
.
001
1
.
63
=
ln
0
.
63
1
.
63
=
5
.
45
.
Column height,
z
=
H
OG
N
OG
=
(2
.
44 ft)(5
.
45)
=
13
.
3ft
.
Example 6.6: packed column absorption
Problem:
Air at 25
◦
Cisused to dry a plastic sheet containing acetone. At the drier exit, the
air leaves containing 0.02 mole fraction acetone. The acetone is to be recovered by
absorption with water in a packed tower. The gas composition is to be reduced to
5
×
10
−
3
=
.
mole fraction at the column exit. The equilibrium relationship is
y
1
8
x
.
The gas enters the bottom of the column (Figure 6.12) at a flux of 1000 lb
m
/
ft
2
·
hr,
and the water enters the top at a flux of 1400 lb
m
/
hr. The tower is packed with
1-inch Berl saddles. Calculate the column height, given:
Water
Sc
L
=
ft
2
·
915
µ
=
12 lb
m
/
ft
·
hr
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