Environmental Engineering Reference
In-Depth Information
V
= 55
Wash solution
HNO
3
=2gmol/L
U, Pu, Zr = 0
V
=333
Extractproduct TBP in kerosene
U
6
Zr
=×
contains 99.99% of the U in the
feed
15
10
Wash
section
V
=55
Raffinate
?
?
U=
Zr =
V
=333
Solvent
U=
Zr =
V
=75
Feed
U=1.8 gmol
?
?
L
HNO
3
=0.95 gmol/L
Zr = 0.046 gmol/L
/
Extraction
section
V
=333
Solvent, TBP in kerosene
U, Pu, Zr=0
V
=130
Aqueous product
containing fission
products
2Zr
U
=×
12
10
5
conc.
in
organic
phase
Distribution coefficient (
K
)=
conc.
in
aqueous
phase
HNO
3
, gmol/L
2.0
1.39
K
U
12
11
K
Pu
8
5
K
Zr
0.06
0.03
Figure 5.31
Diagram and data relating to Problem 5.7.
5.4 For Example 5.3, illustrating minimum solvent flowrate, show that increasing the
solvent flowrate will decrease the required number of equilibrium stages.
5.5 For the same example, show that the maximum concentration of
A
in
O
N
will occur
at the minimum flowrate of solvent.
5.6 In a copper-wire plant, sodium-hydroxide solution (drag-out from a neutralization
bath) is removed from wire coils by countercurrent rinsing with water. At present, the
Search WWH ::
Custom Search