Digital Signal Processing Reference
In-Depth Information
5.14.
(a)
G
1
1
v
2
= 0.02[sinc
1
0.005
1
v + 100p
22
+ sinc
1
0.005
1
v - 100p
22
]
50
p
sinc
5.15.
(a)
g
1
t
2
=
1
10t
2
j0.25v
-0.25v
2
5.16.
(a)
+ 2.5jv + 6
-v
2
(c)
-v
2
+ 5jv + 6
a
np
2
np
2
=
a
n=-
q
10psinc
5.18.
(a)
G
p
1
v
2
b
d
a
v -
b
5.20.
(a)
psinc
1
t
2
5.21.
-4 6 A 6 4
p
j
c
10
10
10 - j50
d
5.22.
(a)
V
2
1
v
2
= V
1
1
v
2
H
1
v
2
=
10 + j50
d
1
v - 50
2
-
1
v + 50
2d
5.27.
(a)
91%
5.28.
(a)
P
y
1
v
2
= 200d
1
v + 200
2
+ 648
1
v + 150
2
+ 648
1
v - 150
2
+ 200
1
v - 200
2
CHAPTER 6
a
n
= p
a
3
6.3.
(a)
Y
1
v
2
n=-3
sinc
2
p
b
d
1
v - n50p
2
1
2
+
2
p
cos
2
3p
cos
y
1
t
2
=
1
50pt
2
+
1
150pt
2
a
n
= p
a
1
(c)
Y
1
v
2
n=-1
sinc
2
p
b
d
1
v - n100p
2
1
2
+
2
p
cos
y
1
t
2
=
1
100pt
2
1
6.5.
H
1
v
2
=
b
.
This is a bandpass filter.
a
vL
1
vRC
1 + j
R
-
V
o
1
v
2
1
6.7.
H
1
v
2
=
=
V
i
1
v
2
v
2
v
c
2
2v
v
c
1 -
+ j
1
1
ƒH
1
v
2
ƒ =
=
2v
2
v
c
v
4
v
c
2v
2
v
c
b
2
d
2
ca
v
v
c
1 -
+
+
1 +
C
C
which is a 2nd order Butterworth frequency response function.
