Digital Signal Processing Reference
In-Depth Information
Signals Periodic in n
We now consider periodic discrete-time signals. By definition, a discrete-time signal
x [ n ] is periodic with period N if
x[n + N] = x[n].
(9.32)
Of course, both n and N are integers.
We first consider the case that the signal x [ n ] is obtained by sampling a sinu-
soidal signal
x(t) = cos (v 0 t)
every T seconds; that is,
x[n] = x(nT).
[ T is the sam-
ple period and not the period of
x(t).
] For x [ n ] to be periodic, from (9.32),
x[n] = cos (nv 0 T) = x[n + N] = cos [(n + N)v 0 T]
= cos (nv 0 T + Nv 0 T).
Hence,
Nv 0 T
must be equal to
2pk,
where k is an integer, because
cos(u +2pk)=
cos u.
Therefore,
2pk = Nv 0 T = N 2p
T 0
k
N =
T
T 0
T Q
,
(9.33)
where is the fundamental period of the continuous-time sinusoid. Thus,
the ratio of the sample period T to the period of the sinusoid
T 0 = 2p/v 0
T 0
must be a ratio of
integers; that is, must be rational .
The result in (9.33) can also be expressed as
T/T 0
NT = kT 0 .
(9.34)
This relation states that there must be exactly N samples in k periods of the signal
This statement applies to the sampling of any periodic continuous-time
cos(v 0 t).
signal
In summary, the sampled signal is periodic if exactly N sam-
ples are taken in exactly every k periods, where N and k are integers. Note the sur-
prising conclusion that the sampling of a periodic continuous-time signal does not
necessarily result in a periodic discrete-time signal. We now give an example.
x(t).
x[n] = cos(nv 0 T)
Sampling of a sinusoid
EXAMPLE 9.6
In this example, we will consider sampling the periodic signal
x(t) = sin pt,
which has the pe-
riod
T 0 = 2p/v 0 = 2 s.
First, we sample with the period
T = 0.5 s.
There are exactly four
samples for each period of sinusoid; in (9.34),
kT 0 = (1) (2) = 2 s
and
NT = 4(0.5) = 2 s.
The signals are illustrated in Figure 9.14(a).
Next, we sample with the period
3
8 T 0 = 0.75 s.
T =
In this case, we have exactly eight
samples in every three periods
(8T = 3T 0 ),
or in every 6 s. These signals are illustrated in
Figure 9.14(b).
As a final example, we sample a triangular wave that is periodic with a period of
This signal is sampled with sample period as shown in Figure 9.14(c).
In this case, there is less than one sample per period of the triangular wave; however,
T= 4 T 0 = 2.5 s,
T 0 = 2 s.
 
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