Civil Engineering Reference
In-Depth Information
T
u
=
2
T
u
,
L
=
2(328
.
7)
=
657
.
4 kN m (485 kip ft)
1
2
(
1
2
(
3
L
)
2
M
u
=
w
u
,
G
+
w
u
,
S
)
L
(0
.
3
L
)
−
w
u
,
G
+
w
u
,
S
)(0
.
+
2
P
u
,
L
(0
.
3
L
)
1
2
(48
1
2
(48
224)
2
=
.
23
+
17
.
98)(24
.
08)(7
.
224)
−
.
23
+
17
.
98)(7
.
+
2(359
.
6)(7
.
224)
=
9227 kN m (6807 kip ft)
Check Outstanding Flanges
Refer to Figure 2.18(a), the parameter
A
cp
/
p
cp
is determined as follows:
Neglect overhanging flanges
1854(203)
1
10
3
mm
2
2
)
A
cp
=
2
(1854
+
1791)(1270
−
203)
=
2321
×
(3597 in
.
p
cp
=
1854
+
1791
+
2(1270)
=
6185 mm (243
.
5in
.
)
A
cp
p
cp
=
2321
2
×
10
6
10
6
mm
3
3
)
=
×
,
.
871
(53
135 in
6185
Include overhanging flanges
10
3
mm
2
10
3
mm
2
2
)
A
cp
=
2321
×
+
(1804)(181)
=
2647
×
(4103 in
.
p
cp
=
3658
+
1791
+
2(159)
+
2(2000)
=
9767 mm (384
.
5in
.
)
A
cp
p
cp
=
2647
2
10
6
×
10
6
mm
3
3
)
10
6
mm
3
=
717
×
(43 783 in
.
<
871
×
NG
.
9767
10
3
mm
2
;
Neglect outstanding flanges and use
A
cp
=
2321
×
p
cp
=
6185 mm; and
A
cp
/
10
6
mm
3
.
p
cp
=
871
×
Check Threshold Torque
10
3
10
3
mm
2
2
)
A
g
=
A
cp
−
A
hole
=
2321
×
−
(1320
×
851)
=
1197
×
(1855 in
.
10
3
P
A
g
=
6076
×
f
pc
=
=
5
.
076 MPa (736 psi)
1197
×
10
3
1
A
g
p
cp
083
f
c
(
MPa
)
f
pc
T
u
=
φ
0
.
+
33
f
c
0
.
083
√
48
2
1197
2
×
10
6
.
5
076
=
.
.
.
+
(0
90)0
1
33
√
48
6185
0
.
.
2
=
215
.
1 kN m (158
.
7kipft)
<
657
.
4 kN m (485 kip ft)
.
Factored torsional moment needs to be considered in design.
