Civil Engineering Reference
In-Depth Information
The position of the neutral axis can be determined by taking the static moments of the
shaded areas (Figure 3.3d), about the centroidal axis (same as neutral axis):
1
2 b ( kd ) 2
mA s ( kd
d )
+
=
nA s ( d
kd )
(3.28)
Dividing Equation (3.28) by bd 2
ρ =
A s /
and denoting
ρ =
A s /
bd and
bd results in:
2 n
ρ d
d
k 2
ρ ) k
+
ρ +
ρ +
=
2( n
m
m
0
(3.29)
Let
ρ
m
β c =
(3.30)
n
ρ
and solving Equation (3.29) by the quadratic equation formula gives:
1
d
d
k
=
( n
ρ
) 2 (1
+ β c ) 2
+
2 n
ρ
+ β c
n
ρ
(1
+ β c )
(3.31)
Equation (3.31) determines the location of the neutral axis for doubly reinforced cracked
beams. For the special case of singly reinforced cracked beams,
β c =
0, and Equation (3.31)
degenerates into Equation (3.23).
The moment resistance of the cross-section M can be calculated from the stress diagram in
Figure 3.3(c) by taking moments about the tensile force:
f c k 1
bd 2
1
2
k
3
A s f s ( d
d )
+
M
=
(3.32)
From Hooke's law and Bernoulli's strain compatibility, (Figure 3.3b), we can express the
compressive rebar stress f s
as
( mE c )
d
d
ε c kd
m ( E c ε c ) kd
f s
E s ε s =
=
=
(3.33)
kd
kd
Substituting f s from Equation (3.33), A s
= ρ bd and m
ρ
=
n
ρβ c into Equation (3.32)
gives:
bd 2 ( E c ε c ) 1
2 k 1
k
1
d
d
d
d
k
3
ρβ c 1
k
M
=
+
n
(3.34)
The curvature can be written according to Bernoulli's hypothesis (Figure 3.3b), as
ε c
kd
φ =
(3.35)
, the cracked moment of inertia I cr for
doubly reinforced sections can be derived according to Equations (3.34) and (3.35):
Since the bending rigidity E c I cr is defined as M
bd 3 1
2 k 2 1
ρβ c k
1
k
3
d
d
d
d
I cr
=
+
n
(3.36)
 
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